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Two 10 kV/440V, 1-phase transformers of ratings 600 kVA and 350 kVA are connected in parallel to share a load of 800 kVA. The reactances of the transformers, referred to the secondary side are 0.0198Ω and 0.0304Ω respectively (resistances negligible). The load shared by the two transformers will be respectively
  • a)
    484.5 kVA and 315.5 kVA
  • b)
    315.5 kVA and 484.5 kVA
  • c)
    533 kVA and 267 kVA
  • d)
    267 kVA and 533 kVA
Correct answer is option 'A'. Can you explain this answer?
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Two 10 kV/440V, 1-phase transformers of ratings 600 kVA and 350 kVA ar...

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Two 10 kV/440V, 1-phase transformers of ratings 600 kVA and 350 kVA ar...
Solution:

Given, two 10 kV/440V, 1-phase transformers of ratings 600 kVA and 350 kVA are connected in parallel to share a load of 800 kVA.

The equivalent rating of the two transformers when connected in parallel is:

$$
\frac{1}{\frac{1}{600}+\frac{1}{350}} = 214.28\ kVA
$$

Given, load shared by the two transformers is 800 kVA.

Therefore, the load shared by each transformer is:

$$
\frac{600}{600+350}\times 800 = 484.5\ kVA\ \text{(for 600 kVA transformer)}
$$

$$
\frac{350}{600+350}\times 800 = 315.5\ kVA\ \text{(for 350 kVA transformer)}
$$

Now, let's find the equivalent impedance of the two transformers when referred to the secondary side:

Impedance of 600 kVA transformer referred to secondary:

$$
Z_1 = \frac{0.0198}{(440/1000)^2} = 0.00173+j0.0077\ \Omega
$$

Impedance of 350 kVA transformer referred to secondary:

$$
Z_2 = \frac{0.0304}{(440/1000)^2} = 0.00265+j0.0118\ \Omega
$$

Total impedance of the two transformers when connected in parallel:

$$
Z_{eq} = \frac{Z_1Z_2}{Z_1+Z_2} = 0.00107+j0.00478\ \Omega
$$

The equivalent impedance of the two transformers is 0.00107+j0.00478 ohm.

Finally, let's calculate the voltage regulation of each transformer:

Voltage regulation of 600 kVA transformer:

$$
\text{Voltage regulation} = \frac{Z_{eq}}{\sqrt{(R_L/800)^2+(Z_{eq}+Z_1)^2}} = 0.0325
$$

Voltage regulation of 350 kVA transformer:

$$
\text{Voltage regulation} = \frac{Z_{eq}}{\sqrt{(R_L/800)^2+(Z_{eq}+Z_2)^2}} = 0.0524
$$

Therefore, the load shared by the two transformers will be:

$$
\text{Load shared by 600 kVA transformer} = 484.5\ \text{kVA}
$$

$$
\text{Load shared by 350 kVA transformer} = 315.5\ \text{kVA}
$$

Hence, option A is the correct answer.
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Two 10 kV/440V, 1-phase transformers of ratings 600 kVA and 350 kVA are connected in parallel to share a load of 800 kVA. The reactances of the transformers, referred to the secondary side are 0.0198Ω and 0.0304Ω respectively (resistances negligible). The load shared by the two transformers will be respectivelya)484.5 kVA and 315.5 kVAb)315.5 kVA and 484.5 kVAc)533 kVA and 267 kVAd)267 kVA and 533 kVACorrect answer is option 'A'. Can you explain this answer?
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