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if tan(A+B)=x and tan(A-B)=y find the value of tan 2A and tan2B
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if tan(A+B)=x and tan(A-B)=y find the value of tan 2A and tan2B
Given:

  • tan(A B) = x

  • tan(A-B) = y



To find:

  • tan 2A

  • tan 2B



Solution:


Using Trigonometric Identities


We can use the following trigonometric identities to find the value of tan 2A and tan 2B.


  • tan 2A = 2tan A / (1 - tan² A)

  • tan 2B = 2tan B / (1 - tan² B)



Finding tan A and tan B


We can use the following identities to find the values of tan A and tan B:


  • tan(A B) = (tan A + tan B) / (1 - tan A * tan B) = x

  • tan(A-B) = (tan A - tan B) / (1 + tan A * tan B) = y



Solving the above equations for tan A and tan B, we get:


  • tan A = (x-y) / (1+xy)

  • tan B = (x+y) / (1-xy)



Substituting tan A and tan B in the identities of tan 2A and tan 2B


Substituting the values of tan A and tan B in the identities of tan 2A and tan 2B, we get:


  • tan 2A = 2 [(x-y) / (1+xy)] / [1 - {(x-y) / (1+xy)}²]

  • tan 2B = 2 [(x+y) / (1-xy)] / [1 - {(x+y) / (1-xy)}²]



Simplifying the expressions for tan 2A and tan 2B


Simplifying the expressions for tan 2A and tan 2B, we get:


  • tan 2A = (2x) / (1-x²-y²)

  • tan 2B = (2y) / (1-x²-y²)



Answer:


  • tan 2A = (2x) / (1-x²-y²)

  • tan 2B = (2y) / (1-x²-y²)

Community Answer
if tan(A+B)=x and tan(A-B)=y find the value of tan 2A and tan2B
we can write 2a= (a+b)+(a-b) and 2b = (a+b)-(a-b)tan(2a) =tan( (a+b)+(a-b) ) = (tan(a+b) +tan(a-b) ) / ( 1-tan(a+b) tan(a-b)) = (x+y) / (1-xy)similarly tan(2b) =tan( (a+b)-(a-b) ) = (tan(a+b) - tan(a-b) ) / ( 1+ tan(a+b) tan(a-b)) = (x-y) / (1+xy)is this answer is right.I think it is right only.
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