Which of the following is a disproportionation reaction?a)CaCO3 + 2H+ ...
A disproportionation reaction is a reaction in which a single element undergoes reduction and oxidation i.e in option d),in Cu2O, Cu has an oxidation state of +1 and in Cu it has 0 (i.e reduction)
and +1 to +2 (i.e oxidation)
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Which of the following is a disproportionation reaction?a)CaCO3 + 2H+ ...
A disproportionation reaction is a reaction in which a single element undergoes reduction and oxidation i.e in Cu2O Cu has an oxidation state of +1 and in cu it has 0(i.e reduction)
and +1 to +2(i.e oxidation)
Which of the following is a disproportionation reaction?a)CaCO3 + 2H+ ...
Disproportionation reaction refers to a type of chemical reaction in which a single substance is simultaneously oxidized and reduced to form two different products. Among the given options, option D: Cu2O + 2H → Cu + Cu2+ + H2O is a perfect example of a disproportionation reaction. Let's break down the reaction and understand it in detail:
Reaction: Cu2O + 2H → Cu + Cu2+ + H2O
**Oxidation process:**
Cu2O loses electrons and gets oxidized to Cu, where the oxidation state of Cu changes from +1 to 0. In this process, Cu2O acts as a reducing agent.
**Reduction process:**
In the presence of H+ ions, Cu2+ ions gain electrons and get reduced to Cu. Here, Cu2+ acts as an oxidizing agent.
Hence, we can conclude that Cu2O is simultaneously oxidized and reduced in this reaction, making it a disproportionation reaction.
Let's summarize the reaction using HTML bullet points:
- Reaction: Cu2O + 2H → Cu + Cu2+ + H2O
- Oxidation: Cu2O (oxidation state: +1) → Cu (oxidation state: 0)
- Reduction: Cu2+ (oxidation state: +2) + 2e- → Cu (oxidation state: 0)
- Disproportionation reaction: Cu2O is simultaneously oxidized and reduced.
It's important to note that the other options (a, b, and c) do not involve a single substance being both oxidized and reduced at the same time. Therefore, option D is the correct answer for the given question.