If the anions(A) form hexagonal closest packing and cations (C) occupy...
Number of A atoms per unit cell in hcp lattice=6. Number of octahedral voids=6 Number of octahedral voids occupied by C = (2/3)*6 = 4 Therefore formula of compound = C4A6 = C2A3
View all questions of this test
If the anions(A) form hexagonal closest packing and cations (C) occupy...
Explanation:
In hexagonal closest packing, the anions form a hexagonal close-packed structure, which can be represented as ABABAB pattern. The cations occupy only 2/3 of the octahedral voids present in this structure.
Therefore, the ratio of cations to anions in the compound can be represented as follows:
- For every two layers of anions (AB), there are three layers of octahedral voids (O).
- The cations occupy only 2/3 of the octahedral voids, which means that for every three octahedral voids, only two are occupied by cations.
Based on the above information, the general formula for the compound can be determined as follows:
- For every two layers of anions (AB), there are three layers of octahedral voids (O).
- The cations occupy only 2/3 of the octahedral voids, which means that for every three octahedral voids, only two are occupied by cations.
- Therefore, the formula of the compound can be represented as C2A3, which means that there are two cations and three anions in the compound.
Therefore, the correct answer is option 'C' (C2A3).
If the anions(A) form hexagonal closest packing and cations (C) occupy...