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 If A1, A2, A3,…., An are n numbers between a and b, such that a, A1, A2, A3,…, An, b are in A.P., then nth term from beginning is:
  • a)
    b
  • b)
    An-1
  • c)
    An
  • d)
    A1
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
If A1, A2, A3,…., Anare n numbers between a and b, such that a, ...
A1,A2,......, An are inserted between a and b then the series will become 
a, A1,A2,A3,......, An,b. Now a becomes the first term, A1 will be second, A2 will become third term
An will become A(n+1)th term 
therefore A(n-1) will become nth term.
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Most Upvoted Answer
If A1, A2, A3,…., Anare n numbers between a and b, such that a, ...
Explanation:

To find the nth term from the beginning in the given arithmetic progression (AP), we need to understand the pattern of the progression.

Let's assume that the common difference between the terms of the AP is 'd'.

Step 1: Identifying the terms in the AP:

The given AP consists of 'n' numbers between 'a' and 'b'. So, the terms in the AP are as follows:

a, A1, A2, A3, ..., An, b

Step 2: Understanding the pattern:

Since the terms in the AP are in the form a, A1, A2, A3, ..., An, b, we can observe that the common difference between consecutive terms is 'd'. Therefore, we can write the terms of the AP as:

a, a+d, a+2d, a+3d, ..., a+(n-1)d, b

Step 3: Finding the nth term from the beginning:

To find the nth term from the beginning, we need to determine the value of An-1.

Since the terms of the AP are in the form a, a+d, a+2d, a+3d, ..., a+(n-1)d, b, the nth term from the beginning is a+(n-1)d.

Therefore, the nth term from the beginning is An-1.

Conclusion:

Hence, the correct answer is option 'B' (An-1).
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Community Answer
If A1, A2, A3,…., Anare n numbers between a and b, such that a, ...
See if A1,A2,......, An are inserted between a and b then the series will become a, A1,A2,A3,......, An, b. Now a becomes the first term, A1 will be second, A2 will become third term, like this An will become A(n+1)th term therefore A(n-1) will become nth term
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In gaseous dissociation reactions, the total mass remains unchanged and the number of moles increases as a result of the reaction. Thus the average molecular weight and hence the vapour density decreases. In other words, the volume increases at constant temperature and pressure and hence the vapour density decreases.The relationship between vapour density in the beginning and vapour density at equilibrium can be found as follows:At constant temperature and constant pressure for a fixed mass of gaseous mixtures,PV = nRT Volume number of molesWhere Do and D are the vapour densities in the beginning and at equilibrium and no and n are the number of moles in the beginning and at equilibrium.The vapour density of PCI5 at 200C and 252C are 70.2 and 57.2 respectively at one atmosphereQ.From the given data, it can be interpreted that .

In gaseous dissociation reactions, the total mass remains unchanged and the number of moles increases as a result of the reaction. Thus the average molecular weight and hence the vapour density decreases. In other words, the volume increases at constant temperature and pressure and hence the vapour density decreases.The relationship between vapour density in the beginning and vapour density at equilibrium can be found as follows:At constant temperature and constant pressure for a fixed mass of gaseous mixtures,PV = nRT Volume number of molesWhere Do and D are the vapour densities in the beginning and at equilibrium and no and n are the number of moles in the beginning and at equilibrium.The vapour density of PCI5 at 200C and 252C are 70.2 and 57.2 respectively at one atmosphereQ.This observation shows that

In gaseous dissociation reactions, the total mass remains unchanged and the number of moles increases as a result of the reaction. Thus the average molecular weight and hence the vapour density decreases. In other words, the volume increases at constant temperature and pressure and hence the vapour density decreases.The relationship between vapour density in the beginning and vapour density at equilibrium can be found as follows:At constant temperature and constant pressure for a fixed mass of gaseous mixtures,PV = nRT Volume number of molesWhere Do and D are the vapour densities in the beginning and at equilibrium and no and n are the number of moles in the beginning and at equilibrium.The vapour density of PCI5 at 200C and 252C are 70.2 and 57.2 respectively at one atmosphereQ.The observation shows that the dissociation constants (KP) for the reaction are

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If A1, A2, A3,…., Anare n numbers between a and b, such that a, A1, A2, A3,…, An, b are in A.P., then nthterm from beginning is:a)bb)An-1c)And)A1Correct answer is option 'B'. Can you explain this answer?
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