Calculating Acceleration of a Bicycle
Acceleration can be calculated using the formula:
\[ a = \frac{v_f - v_i}{t} \]
Where:
- \( a \) = acceleration
- \( v_f \) = final velocity
- \( v_i \) = initial velocity
- \( t \) = time taken

Given Data:
- Initial velocity (\( v_i \)) = 10 km/h
- Final velocity (\( v_f \)) = 15 km/h
- Time taken (\( t \)) = 6 seconds

Calculating Acceleration:
Substitute the given values into the formula:
\[ a = \frac{15 - 10}{6} \]
\[ a = \frac{5}{6} \]
\[ a = 0.83 \, m/s^2 \]
Therefore, the acceleration of the bicycle is 0.83 m/s².

Explanation:
When the bicycle increases its velocity from 10 km/h to 15 km/h in 6 seconds, it undergoes acceleration. Acceleration is the rate of change of velocity with respect to time. In this case, the acceleration is positive as the velocity of the bicycle is increasing. The acceleration value of 0.83 m/s² indicates that the bicycle's velocity is increasing by 0.83 meters per second every second. This acceleration allows the bicycle to reach its final velocity of 15 km/h from the initial velocity of 10 km/h in the given time frame.

V=u+at15*5/18=10*5/18+a*64.17=2.78+a*61.39 =a*6a=1.39/6a=.23 m/s2