JEE Question

1-Phenylethanol can be prepared by the reaction of benzaldehyde with
  • a)
    Methyl bromide
  • b)
    Ethyl iodide and magnesium
  • c)
    Methyl iodide and magnesium
  • d)
    Methyl bromide and aluminium bromide
Correct answer is option 'C'. Can you explain this answer?

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Answers

Anand Kumar
Oct 14, 2018
Explanation:1- phenylethanol is prepared by reacting benzaldehyde with methyl magnesium iodide or by mixture of methyl iodide and magnesium as:CH3I. + Mg. ----------------> CH3MgI ( in presence of dry ether.)This reaction can also be done in case of aromatic.Hence, correct answer is (c).

Niloni Soni
Nov 16, 2018
It's grignard reaction . Whenever carbonyl is given and in product alcohol is formed RMgX must be used where R= alkyl group;X=halogen. As benzaldehyde is given and 1 phenylethanol is formed so alkyl group containing one carbon must be used so answer is c

Golla Ramesh
4 weeks ago
Answer-C correct and grignard reaction CH3-Mg-I it gives CH3-CH2-(OH)-Ph

Explanation:1- phenylethanol is prepared by reacting benzaldehyde with methyl magnesium iodide or by mixture of methyl iodide and magnesium as:CH3I. + Mg. ----------------> CH3MgI ( in presence of dry ether.)This reaction can also be done in case of aromatic.Hence, correct answer is (c).

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Explanation:1- phenylethanol is prepared by reacting benzaldehyde with methyl magnesium iodide or by mixture of methyl iodide and magnesium as:CH3I. + Mg. ----------------> CH3MgI ( in presence of dry ether.)This reaction can also be done in case of aromatic.Hence, correct answer is (c).