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1-Phenylethanol can be prepared by the reaction of benzaldehyde with
- a)Methyl bromide
- b)Ethyl iodide and magnesium
- c)Methyl iodide and magnesium
- d)Methyl bromide and aluminium bromide
Correct answer is option 'C'. Can you explain this answer?
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1-Phenylethanol can be prepared by the reaction of benzaldehyde witha)...
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Explanation:1- phenylethanol is prepared by reacting benzaldehyde with methyl magnesium iodide or by mixture of methyl iodide and magnesium as:CH3I. + Mg. ----------------> CH3MgI ( in presence of dry ether.)This reaction can also be done in case of aromatic.Hence, correct answer is (c).
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1-Phenylethanol can be prepared by the reaction of benzaldehyde witha)...
Preparation of 1-Phenylethanol from Benzaldehyde
The reaction of benzaldehyde with methyl iodide and magnesium can be used to prepare 1-phenylethanol.
Reaction Scheme:
Benzaldehyde + CH3I + Mg → 1-Phenylethanol
Explanation:
Benzaldehyde is treated with methyl iodide and magnesium to produce 1-phenylethanol. The reaction is carried out in the presence of anhydrous ether as a solvent.
The reaction mechanism involves the formation of a Grignard reagent by the reaction of magnesium with methyl iodide. The Grignard reagent then attacks the carbonyl group of benzaldehyde to form a tertiary alcohol, 1-phenylethanol.
The reaction can also be carried out with other alkyl halides like ethyl iodide, but the use of methyl iodide is preferred because it leads to a higher yield of the desired product.
Advantages of the Reaction:
1. High yield of product
2. Easy to carry out
3. Simple apparatus requirement
4. Easily scalable
5. Can be used to prepare a wide range of tertiary alcohols.
Conclusion:
1-Phenylethanol can be prepared by the reaction of benzaldehyde with methyl iodide and magnesium. This reaction is a simple and efficient method for the preparation of tertiary alcohols.
The reaction of benzaldehyde with methyl iodide and magnesium can be used to prepare 1-phenylethanol.
Reaction Scheme:
Benzaldehyde + CH3I + Mg → 1-Phenylethanol
Explanation:
Benzaldehyde is treated with methyl iodide and magnesium to produce 1-phenylethanol. The reaction is carried out in the presence of anhydrous ether as a solvent.
The reaction mechanism involves the formation of a Grignard reagent by the reaction of magnesium with methyl iodide. The Grignard reagent then attacks the carbonyl group of benzaldehyde to form a tertiary alcohol, 1-phenylethanol.
The reaction can also be carried out with other alkyl halides like ethyl iodide, but the use of methyl iodide is preferred because it leads to a higher yield of the desired product.
Advantages of the Reaction:
1. High yield of product
2. Easy to carry out
3. Simple apparatus requirement
4. Easily scalable
5. Can be used to prepare a wide range of tertiary alcohols.
Conclusion:
1-Phenylethanol can be prepared by the reaction of benzaldehyde with methyl iodide and magnesium. This reaction is a simple and efficient method for the preparation of tertiary alcohols.
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1-Phenylethanol can be prepared by the reaction of benzaldehyde witha) Methyl bromide b) Ethyl iodide and magnesium c) Methyl iodide and magnesium d) Methyl bromide and aluminium bromide Correct answer is option 'C'. Can you explain this answer?
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1-Phenylethanol can be prepared by the reaction of benzaldehyde witha) Methyl bromide b) Ethyl iodide and magnesium c) Methyl iodide and magnesium d) Methyl bromide and aluminium bromide Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 1-Phenylethanol can be prepared by the reaction of benzaldehyde witha) Methyl bromide b) Ethyl iodide and magnesium c) Methyl iodide and magnesium d) Methyl bromide and aluminium bromide Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1-Phenylethanol can be prepared by the reaction of benzaldehyde witha) Methyl bromide b) Ethyl iodide and magnesium c) Methyl iodide and magnesium d) Methyl bromide and aluminium bromide Correct answer is option 'C'. Can you explain this answer?.
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