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Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. a horizontal force F = 600 N is applied to the 20 kg mass so as to pull it. What is the tension in the string?
- a)250 N
- b)300 N
- c)150 N
- d)200 N
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, ho...
For some instance assume both masses as one system, thus we get that
600 = 30a
Where a is the common acceleration of the system.
Now if we consider the 10kg block we get that
T = 10a
And a = 20m/s2
Thus we get T = 200N
600 = 30a
Where a is the common acceleration of the system.
Now if we consider the 10kg block we get that
T = 10a
And a = 20m/s2
Thus we get T = 200N
Most Upvoted Answer
Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, ho...
Given:
Mass of first body, m1 = 10 kg
Mass of second body, m2 = 20 kg
Force applied on the second body, F = 600 N
To find: Tension in the string
Assumptions:
1. The string is light and inextensible.
2. The surface is smooth and frictionless.
Solution:
As per the problem statement, the two bodies are tied to the ends of a light string. Therefore, the tension in the string will be same for both the bodies. Let us assume this tension to be T.
Now, let us consider the motion of the second body (of mass 20 kg) which is being pulled by the force F. As there is no resistance offered by the smooth surface, the force F will accelerate the second body. Let us assume this acceleration to be a.
Using Newton's Second Law of motion, we can write the equation of motion for the second body as:
F - T = m2a
where F is the applied force and T is the tension in the string.
Now, let us consider the motion of the first body (of mass 10 kg). As both the bodies are tied to the same string, they will move together. Therefore, the acceleration of the first body will be same as that of the second body. Let us assume this acceleration to be a as well.
Using Newton's Second Law of motion, we can write the equation of motion for the first body as:
T = m1a
Substituting the value of a from the first equation into the second equation, we get:
T = m1(F - T)/m2
Solving for T, we get:
T = m1F/(m1 + m2)
Substituting the given values, we get:
T = (10 x 600)/(10 + 20) = 200 N
Therefore, the tension in the string is 200 N.
Answer: d) 200 N
Mass of first body, m1 = 10 kg
Mass of second body, m2 = 20 kg
Force applied on the second body, F = 600 N
To find: Tension in the string
Assumptions:
1. The string is light and inextensible.
2. The surface is smooth and frictionless.
Solution:
As per the problem statement, the two bodies are tied to the ends of a light string. Therefore, the tension in the string will be same for both the bodies. Let us assume this tension to be T.
Now, let us consider the motion of the second body (of mass 20 kg) which is being pulled by the force F. As there is no resistance offered by the smooth surface, the force F will accelerate the second body. Let us assume this acceleration to be a.
Using Newton's Second Law of motion, we can write the equation of motion for the second body as:
F - T = m2a
where F is the applied force and T is the tension in the string.
Now, let us consider the motion of the first body (of mass 10 kg). As both the bodies are tied to the same string, they will move together. Therefore, the acceleration of the first body will be same as that of the second body. Let us assume this acceleration to be a as well.
Using Newton's Second Law of motion, we can write the equation of motion for the first body as:
T = m1a
Substituting the value of a from the first equation into the second equation, we get:
T = m1(F - T)/m2
Solving for T, we get:
T = m1F/(m1 + m2)
Substituting the given values, we get:
T = (10 x 600)/(10 + 20) = 200 N
Therefore, the tension in the string is 200 N.
Answer: d) 200 N
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Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. a horizontal force F = 600 N is applied to the 20 kg mass so as to pull it. What is the tension in the string?a)250 Nb)300 Nc)150 Nd)200 NCorrect answer is option 'D'. Can you explain this answer?
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Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. a horizontal force F = 600 N is applied to the 20 kg mass so as to pull it. What is the tension in the string?a)250 Nb)300 Nc)150 Nd)200 NCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. a horizontal force F = 600 N is applied to the 20 kg mass so as to pull it. What is the tension in the string?a)250 Nb)300 Nc)150 Nd)200 NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. a horizontal force F = 600 N is applied to the 20 kg mass so as to pull it. What is the tension in the string?a)250 Nb)300 Nc)150 Nd)200 NCorrect answer is option 'D'. Can you explain this answer?.
Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. a horizontal force F = 600 N is applied to the 20 kg mass so as to pull it. What is the tension in the string?a)250 Nb)300 Nc)150 Nd)200 NCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. a horizontal force F = 600 N is applied to the 20 kg mass so as to pull it. What is the tension in the string?a)250 Nb)300 Nc)150 Nd)200 NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. a horizontal force F = 600 N is applied to the 20 kg mass so as to pull it. What is the tension in the string?a)250 Nb)300 Nc)150 Nd)200 NCorrect answer is option 'D'. Can you explain this answer?.
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