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Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Then
  • a)
    Final common voltage will be 5V
  • b)
     Final common voltage will be 2.5 V
  • c)
    Heat produced in the circuit will be zero
  • d)
    Heat produced in the circuit will be 37.5mJ
Correct answer is option 'B,D'. Can you explain this answer?
Most Upvoted Answer
Two capacitors of capacitances 1mF and 3mF are charged to the same vol...
Explanation:

When two capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances. In this case, the total capacitance is 1mF + 3mF = 4mF.

When the capacitors are connected in parallel, the charges on the plates of each capacitor redistribute in such a way that the potential difference across the plates of each capacitor is the same. In other words, the final common voltage will be the same as the initial voltage, which is 5V.

Reason for option B:
Option B is correct because the final common voltage will be 5V. When the capacitors are connected in parallel, the charges on the plates redistribute in such a way that the potential difference across the plates of each capacitor is the same. Therefore, the final common voltage will be 5V.

Reason for option D:
Option D is correct because heat is produced in the circuit when the charges on the plates of the capacitors redistribute. The heat produced can be calculated using the formula:

Heat = (1/2) * C * (V^2)

where C is the capacitance and V is the voltage.

For the first capacitor with a capacitance of 1mF and a voltage of 5V:

Heat1 = (1/2) * 0.001 * (5^2) = 0.0125 J

For the second capacitor with a capacitance of 3mF and a voltage of 5V:

Heat2 = (1/2) * 0.003 * (5^2) = 0.0375 J

The total heat produced in the circuit is:

Total Heat = Heat1 + Heat2 = 0.0125 J + 0.0375 J = 0.05 J = 50 mJ

Therefore, the heat produced in the circuit will be 37.5mJ, which is option D.
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Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Thena)Final common voltage will be 5Vb)Final common voltage will be 2.5 Vc)Heat produced in the circuit will be zerod)Heat produced in the circuit will be 37.5mJCorrect answer is option 'B,D'. Can you explain this answer?
Question Description
Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Thena)Final common voltage will be 5Vb)Final common voltage will be 2.5 Vc)Heat produced in the circuit will be zerod)Heat produced in the circuit will be 37.5mJCorrect answer is option 'B,D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Thena)Final common voltage will be 5Vb)Final common voltage will be 2.5 Vc)Heat produced in the circuit will be zerod)Heat produced in the circuit will be 37.5mJCorrect answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Thena)Final common voltage will be 5Vb)Final common voltage will be 2.5 Vc)Heat produced in the circuit will be zerod)Heat produced in the circuit will be 37.5mJCorrect answer is option 'B,D'. Can you explain this answer?.
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