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Find the value of k for which the quadratic equation 9x^2-3k+k =0 has equal roots?
Most Upvoted Answer
Find the value of k for which the quadratic equation 9x^2-3k+k =0 has ...
For having equal roots discriminant=0
or,b^2-4AC=0
(-3k)^2-4(9)(k)=0
9k^2-36k=0
9k^2=36k
k=36k/9k
k=4
Community Answer
Find the value of k for which the quadratic equation 9x^2-3k+k =0 has ...
Finding the Value of k for Equal Roots in a Quadratic Equation:
To find the value of k for which the quadratic equation 9x^2-3k+k=0 has equal roots, we need to first determine the conditions for equal roots in a quadratic equation.

Condition for Equal Roots:
For a quadratic equation ax^2 + bx + c = 0 to have equal roots, the discriminant (b^2 - 4ac) should be equal to zero.

Given Quadratic Equation:
9x^2 - 3kx + k = 0

Finding Discriminant:
In this case, a = 9, b = -3k, and c = k.
The discriminant is calculated as: (-3k)^2 - 4*9*k = 0
9k^2 - 36k = 0
k(9k - 36) = 0

Solving for k:
Setting k(9k - 36) = 0, we get two possible solutions:
1. k = 0
2. 9k - 36 = 0
9k = 36
k = 4

Conclusion:
Therefore, the value of k for which the quadratic equation 9x^2-3kx+k=0 has equal roots is k = 0 or k = 4. These values satisfy the condition of having a discriminant equal to zero, indicating equal roots for the quadratic equation.
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