In a meter bridge experiment a balance point is obtained at a distance...
60/40 = l/100-l, = R/8
so R=12
now changed position 8 is proportional to l and 12 to (100-l)
8/12 = l/100-l
l = 40ohm
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In a meter bridge experiment a balance point is obtained at a distance...
Explanation:
In a meter bridge experiment, a balance point is obtained at a distance of 60 cm from the left end when unknown resistance R is in a left gap and 8 ohms resistor is connected in the right gap. When the position of R and 8 ohm resistor is interchanged the balance point will be at a distance of 40 cm.
Reasoning:
The meter bridge experiment is based on the principle of Wheatstone's bridge. It is used to measure the unknown resistance of a conductor. The bridge consists of a long uniform wire AB, a resistance box, a galvanometer, and a battery. The wire AB is divided into two parts with a length ratio of 1:1. The resistance box is connected between the points C and D. The galvanometer is connected between the point B and the point E. The battery is connected between the points A and the point E.
Balance Point:
In a meter bridge experiment, the balance point is defined as the point on the wire where the galvanometer shows zero deflection. At this point, the potential difference between the two points on the wire is equal.
Calculation:
Let R be the unknown resistance.
Let x be the distance of the balance point from the left end when R is in the left gap.
Let l be the length of the wire from the left end to the balance point when R is in the left gap.
Then, the length of the wire from the balance point to the right end is (100 - l).
According to the principle of Wheatstone's bridge, the ratio of the resistances in the two gaps is equal to the ratio of the lengths of the wire segments on either side of the balance point.
Therefore, we have:
R/8 = l/(100 - l)
Solving for l, we get:
l = 60 cm
Therefore, the balance point is at a distance of 60 cm from the left end when R is in the left gap and 8 ohms resistor is connected in the right gap.
When the position of R and 8 ohm resistor is interchanged, the ratio of the resistances in the two gaps is reversed.
Therefore, we have:
8/R = (100 - l)/l
Solving for l, we get:
l = 40 cm
Therefore, the balance point is at a distance of 40 cm from the left end when 8 ohms resistor is in the left gap and R is connected in the right gap.
Therefore, the correct answer is option 'A' (40 cm).
In a meter bridge experiment a balance point is obtained at a distance...
60/40=l/100-l,=R/8
so R=12
now changed position 8is proportional to l and 12 to (100-l)
8/12=l/100-l
l=40