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In induction motor air gap power is 10 kW and mechanically developed power is 8 kW. Wha tare the rotor ohmic losses?
- a)1 kW
- b)3 kW
- c)2 kW
- d)0.5 kW
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
In induction motor air gap power is 10 kW and mechanically developed p...
Rotor ohmic loss = air gap power or rotor input power - mechanical developed power by rotor (∵ Rotor core losses are neglected due to low rotor frequency)
Rotor ohmic loss = 10-8 ⇒ 2 kW.
Most Upvoted Answer
In induction motor air gap power is 10 kW and mechanically developed p...
Answer:
Given, air gap power (Pg) = 10 kW
Mechanically developed power (Pmd) = 8 kW
Rotor ohmic losses refer to the power lost in the rotor due to resistance of the rotor winding. It can be calculated using the following formula:
Rotor ohmic losses = Pg - Pmd
Therefore, rotor ohmic losses = 10 kW - 8 kW = 2 kW
Hence, the correct option is (c) 2 kW.
Explanation:
The explanation for the solution of the problem is as follows:
- Induction motor: It is a type of AC motor in which the rotor rotates due to electromagnetic induction.
- Air gap power (Pg): It is the power developed in the air gap of the motor due to the interaction of the magnetic fields of the stator and rotor.
- Mechanically developed power (Pmd): It is the power developed by the rotor due to its rotation.
- Rotor ohmic losses: It is the power lost in the rotor due to its resistance.
The rotor ohmic losses can be calculated by subtracting the mechanically developed power from the air gap power. In the given problem, the air gap power is 10 kW and the mechanically developed power is 8 kW. Therefore, the rotor ohmic losses can be calculated as follows:
Rotor ohmic losses = Air gap power - Mechanically developed power
= 10 kW - 8 kW
= 2 kW
Hence, the correct option is (c) 2 kW.
Given, air gap power (Pg) = 10 kW
Mechanically developed power (Pmd) = 8 kW
Rotor ohmic losses refer to the power lost in the rotor due to resistance of the rotor winding. It can be calculated using the following formula:
Rotor ohmic losses = Pg - Pmd
Therefore, rotor ohmic losses = 10 kW - 8 kW = 2 kW
Hence, the correct option is (c) 2 kW.
Explanation:
The explanation for the solution of the problem is as follows:
- Induction motor: It is a type of AC motor in which the rotor rotates due to electromagnetic induction.
- Air gap power (Pg): It is the power developed in the air gap of the motor due to the interaction of the magnetic fields of the stator and rotor.
- Mechanically developed power (Pmd): It is the power developed by the rotor due to its rotation.
- Rotor ohmic losses: It is the power lost in the rotor due to its resistance.
The rotor ohmic losses can be calculated by subtracting the mechanically developed power from the air gap power. In the given problem, the air gap power is 10 kW and the mechanically developed power is 8 kW. Therefore, the rotor ohmic losses can be calculated as follows:
Rotor ohmic losses = Air gap power - Mechanically developed power
= 10 kW - 8 kW
= 2 kW
Hence, the correct option is (c) 2 kW.
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In induction motor air gap power is 10 kW and mechanically developed power is 8 kW. Wha tare the rotor ohmic losses?a)1 kWb)3 kWc)2 kWd)0.5 kWCorrect answer is option 'C'. Can you explain this answer?
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