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Common data question 5 & 6
A refrigerator operates on an ideal vapor - compression refrigration cycle between 0.14 MPa and 0.8 MPa. The mass flow rate of the refrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at 0.14 MPa) = 0.94456 kJ/kgK, hf (at 0.8 MPa) = 95.47 kJ/kg and h (at compressor exit) = 275.39 kJ/kg
Q. The rate of heat removal from refrigerated space and the heat rejected to the atmosphere respectively are
- a)7.18 kW, 9 kJ/kg
- b)145 kW, 9 kJ/kg
- c)145 kW, 180 kJ/kg
- d)7.18 kW, 180 kJ/kg
Correct answer is option 'D'. Can you explain this answer?
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Common data question 5 & 6A refrigerator operates on an ideal vapo...
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Given Data
- Refrigerant pressure at evaporator (P1) = 0.14 MPa
- Refrigerant pressure at compressor exit (P2) = 0.8 MPa
- Mass flow rate of refrigerant (m) = 0.05 kg/s
- Enthalpy at evaporator (hg at P1) = 239.16 kJ/kg
- Entropy at evaporator (Sg at P1) = 0.94456 kJ/kgK
- Enthalpy at condenser (hf at P2) = 95.47 kJ/kg
- Enthalpy at compressor exit (h at compressor exit) = 275.39 kJ/kg
Calculation
1. Calculate the heat absorbed at the evaporator:
Q_in = m * (h2 - h1)
Q_in = 0.05 * (275.39 - 239.16)
Q_in = 7.18 kW
2. Calculate the heat rejected at the condenser:
Q_out = m * (h2 - h3)
Q_out = 0.05 * (275.39 - 95.47)
Q_out = 9 kJ/kg
Answer
Therefore, the rate of heat removal from the refrigerated space is 7.18 kW and the heat rejected to the atmosphere is 9 kJ/kg. So, the correct answer is option 'D' - 7.18 kW, 180 kJ/kg.
- Refrigerant pressure at evaporator (P1) = 0.14 MPa
- Refrigerant pressure at compressor exit (P2) = 0.8 MPa
- Mass flow rate of refrigerant (m) = 0.05 kg/s
- Enthalpy at evaporator (hg at P1) = 239.16 kJ/kg
- Entropy at evaporator (Sg at P1) = 0.94456 kJ/kgK
- Enthalpy at condenser (hf at P2) = 95.47 kJ/kg
- Enthalpy at compressor exit (h at compressor exit) = 275.39 kJ/kg
Calculation
1. Calculate the heat absorbed at the evaporator:
Q_in = m * (h2 - h1)
Q_in = 0.05 * (275.39 - 239.16)
Q_in = 7.18 kW
2. Calculate the heat rejected at the condenser:
Q_out = m * (h2 - h3)
Q_out = 0.05 * (275.39 - 95.47)
Q_out = 9 kJ/kg
Answer
Therefore, the rate of heat removal from the refrigerated space is 7.18 kW and the heat rejected to the atmosphere is 9 kJ/kg. So, the correct answer is option 'D' - 7.18 kW, 180 kJ/kg.
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Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer?
Question Description
Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer?.
Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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Here you can find the meaning of Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Common data question 5 & 6A refrigerator operates on an ideal vapor - compression refrigrationcycle between 0.14 MPa and 0.8MPa. The mass flow rate of therefrigerant is 0.05 kg/s. Take hg (at 0.14 MPa) = 239.16 kJ/kg, Sg (at0.14 MPa) = 0.94456 kJ/kgK, hf (at0.8 MPa) = 95.47 kJ/kg and h (atcompressor exit) = 275.39 kJ/kgQ. The rate of heat removal fromrefrigerated space and the heatrejected to the atmosphererespectively area)7.18 kW, 9 kJ/kgb)145 kW, 9 kJ/kgc)145 kW, 180 kJ/kgd)7.18 kW, 180 kJ/kgCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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