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Nickel (Z = 28) combines with a ninegative monodentate ligand X_ to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]
- a)One, square planar
- b)Two, square planar
- c)One, tetrahedral
- d)Two, tetrahedral
Correct answer is option 'D'. Can you explain this answer?
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Paramagnetic Complex Formation of [NiX4]2-
Unpaired Electrons in Nickel:
- The complex [NiX4]2- has a total charge of 2-.
- Since each X- ligand has a charge of -1, the total charge contributed by X ligands is 4-.
- Therefore, the charge on nickel (Ni) in the complex is 2+.
- Nickel (Ni) in its neutral state has 2 unpaired electrons.
- When it forms the complex [NiX4]2-, the 2+ charge means it loses 2 electrons.
- Hence, in the complex, nickel will have 2 unpaired electrons.
Geometry of the Complex Ion:
- The coordination number of nickel in the complex is 4, as it forms a complex with four monodentate X- ligands.
- The geometry of a complex with a coordination number of 4 is tetrahedral.
- Therefore, the complex ion [NiX4]2- has a tetrahedral geometry.
Therefore, the correct answer is option 'D', which states that the complex [NiX4]2- has two unpaired electrons in nickel and a tetrahedral geometry.
Unpaired Electrons in Nickel:
- The complex [NiX4]2- has a total charge of 2-.
- Since each X- ligand has a charge of -1, the total charge contributed by X ligands is 4-.
- Therefore, the charge on nickel (Ni) in the complex is 2+.
- Nickel (Ni) in its neutral state has 2 unpaired electrons.
- When it forms the complex [NiX4]2-, the 2+ charge means it loses 2 electrons.
- Hence, in the complex, nickel will have 2 unpaired electrons.
Geometry of the Complex Ion:
- The coordination number of nickel in the complex is 4, as it forms a complex with four monodentate X- ligands.
- The geometry of a complex with a coordination number of 4 is tetrahedral.
- Therefore, the complex ion [NiX4]2- has a tetrahedral geometry.
Therefore, the correct answer is option 'D', which states that the complex [NiX4]2- has two unpaired electrons in nickel and a tetrahedral geometry.
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Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer?
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Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer?.
Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer?.
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Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Nickel (Z = 28) combines with a ninegative monodentate ligand X_to form a paramagnetic complex [NiX4]2_. The number of unpaired electron in the nickel and geometry of this complex ion are respectively – [AIEEE-2006]a)One, square planarb)Two, square planarc)One, tetrahedrald)Two, tetrahedralCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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