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A bag contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the bag, if at least one black ball is to be included in the draw? 

  • a)
    64

  • b)
    128

  • c)
    32

  • d)
    None of these

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A bag contains 2 white balls, 3 black balls and 4 red balls. In how ma...
The bag contains 2 White, 3 Black and 4 Red balls.


So, total 9 balls are there in the bag; among them 3 are Black and 6 are non-Black balls.


Three balls can randomly be drawn in (9C3) = 84 ways.


1 Black and 2 non-Black balls can be drawn in (3C1)*(6C2) = 45 ways.


1 non-Black and 2 Black balls can be drawn in (6C1)*(3C2) = 18 ways.


3 Black balls can be drawn in (3C3) = 1 way.


So, three balls drawn in (45 + 18 + 1) = 64 ways will have at least one Black ball among the drawn ones.
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Most Upvoted Answer
A bag contains 2 white balls, 3 black balls and 4 red balls. In how ma...
Take this question as : 3 black balls and 6 non-black balls
req = all possible ways to drawn 3 balls - no black ball drawn
= 9C3 - 6C3
= 84 - 20 = 64

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Community Answer
A bag contains 2 white balls, 3 black balls and 4 red balls. In how ma...
Given: A bag contains 2 white balls, 3 black balls and 4 red balls.

To find: In how many ways can 3 balls be drawn from the bag, if at least one black ball is to be included in the draw?

Solution:

Total number of ways of drawing 3 balls from the bag = 9C3 = (9 x 8 x 7)/(3 x 2 x 1) = 84

Let us now calculate the number of ways in which no black ball is drawn.

Number of ways of drawing 3 balls from the 6 non-black balls = 6C3 = (6 x 5 x 4)/(3 x 2 x 1) = 20

∴ Number of ways of drawing at least one black ball = Total number of ways of drawing 3 balls – Number of ways of drawing no black ball

= 84 – 20

= 64

Hence, the correct answer is option (a) 64.
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A bag contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the bag, if at least one black ball is to be included in the draw?a)64b)128c)32d)None of theseCorrect answer is option 'A'. Can you explain this answer?
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