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A urn contains 4 red balls, 5 green balls and 6 white balls, if one ball is drawn at random, find the probability that it is neither red nor white.
  • a)
    1/3
  • b)
    1/4
  • c)
    1/5
  • d)
    2/3
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A urn contains 4 red balls, 5 green balls and 6 white balls, if one ba...
5c1/15c1 = 1/3
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Most Upvoted Answer
A urn contains 4 red balls, 5 green balls and 6 white balls, if one ba...

Solution:

Total number of balls in the urn:
- Total number of balls = 4 (red) + 5 (green) + 6 (white) = 15

Number of balls that are neither red nor white:
- Number of green balls = 5

Probability of drawing a ball that is neither red nor white:
- Probability = Number of favorable outcomes / Total number of outcomes
- Probability = Number of green balls / Total number of balls
- Probability = 5 / 15
- Probability = 1/3

Therefore, the probability that a ball drawn at random is neither red nor white is 1/3, which corresponds to option 'A'.
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A urn contains 4 red balls, 5 green balls and 6 white balls, if one ball is drawn at random, find the probability that it is neither red nor white.a)1/3b)1/4c)1/5d)2/3e)None of theseCorrect answer is option 'A'. Can you explain this answer?
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