The radius of hydrogen atom in the ground state 0.53 Armstrong the rad...
Radius is 0.529xn^2/z ...for H n=1 and z=1 ..it is given in question radius is 0.53 angstrom. for Be z=4 and n=1 as we are talking about the same state. radius=0.53x1/4
The radius of hydrogen atom in the ground state 0.53 Armstrong the rad...
The radius of hydrogen atom in the ground state is 0.53 Å (Angstrom). Now, let's determine the radius of the Be3+ ion in a similar state.
Hydrogen Atom Radius:
The ground state of a hydrogen atom refers to the lowest energy state of the atom where the electron is in its lowest possible energy level. In this state, the electron is located in the 1s orbital, which is a spherical region around the nucleus.
The radius of the hydrogen atom in the ground state is given by the Bohr radius (a0), which is approximately 0.53 Å. The Bohr radius is a fundamental constant that represents the typical size of a hydrogen atom in its ground state.
Be3+ Ion Radius:
To determine the radius of the Be3+ ion in a similar state, we need to consider the electronic configuration of the ion. Be3+ ion is formed when a beryllium atom loses three electrons.
The electronic configuration of Be3+ ion is 1s2, which means it has two electrons. Since Be3+ has a higher nuclear charge compared to hydrogen, the remaining two electrons are attracted more strongly to the nucleus. As a result, the electron cloud becomes more contracted and the radius of the ion decreases.
The decrease in radius can be explained by the concept of effective nuclear charge. The effective nuclear charge experienced by an electron is the net positive charge felt by the electron after accounting for the shielding effect of other electrons. In the case of Be3+, the effective nuclear charge experienced by the remaining two electrons is significantly higher compared to hydrogen, leading to a smaller radius.
Comparison:
Now, let's compare the radius of the hydrogen atom in the ground state (0.53 Å) with the radius of the Be3+ ion.
Due to the higher effective nuclear charge, the radius of the Be3+ ion would be smaller than that of the hydrogen atom in the ground state. However, the exact value of the radius of the Be3+ ion depends on various factors such as the atomic structure, electron-electron repulsion, and quantum mechanical effects.
In conclusion, the radius of the Be3+ ion in a similar state to the hydrogen atom in the ground state would be smaller than 0.53 Å. The exact value can be determined through calculations and experimental data.