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A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt?
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A ball of mass 0.25 kg attached to the end of the strings of length 1....
**Centripetal Force and Tension in Circular Motion**
When an object moves in a circular path, it experiences a force called the centripetal force, which is directed towards the center of the circle. In this case, the ball attached to the string is rotating in a horizontal circle. The tension in the string provides the necessary centripetal force to keep the ball moving in a circular path.
**Determining the Maximum Velocity**
To determine the maximum velocity at which the ball can be rotated without breaking the string, we need to find the maximum tension in the string and then use it to calculate the maximum velocity.
**Finding the Maximum Tension**
According to the problem, the string will break if the tension exceeds 25N. Therefore, we need to find the tension in the string when the ball is rotating at the maximum velocity.
**Centripetal Force and Tension Relationship**
The tension in the string is equal to the centripetal force required to keep the ball moving in a circular path. This can be calculated using the equation:
Tension = (mass * velocity^2) / radius
where:
- Tension is the tension in the string
- mass is the mass of the ball (0.25 kg)
- velocity is the velocity of the ball
- radius is the length of the string (1.96 m)
**Calculating the Maximum Tension**
To find the maximum tension, we substitute the maximum velocity into the above equation and solve for tension:
25 N = (0.25 kg * velocity^2) / 1.96 m
Rearranging the equation, we get:
velocity^2 = (25 N * 1.96 m) / 0.25 kg
velocity^2 = 196 N*m / 0.25 kg
velocity^2 = 784 N*m/kg
velocity = √(784 N*m/kg)
velocity ≈ 28 m/s
Therefore, the maximum velocity at which the ball can be rotated without breaking the string is approximately 28 m/s.
When an object moves in a circular path, it experiences a force called the centripetal force, which is directed towards the center of the circle. In this case, the ball attached to the string is rotating in a horizontal circle. The tension in the string provides the necessary centripetal force to keep the ball moving in a circular path.
**Determining the Maximum Velocity**
To determine the maximum velocity at which the ball can be rotated without breaking the string, we need to find the maximum tension in the string and then use it to calculate the maximum velocity.
**Finding the Maximum Tension**
According to the problem, the string will break if the tension exceeds 25N. Therefore, we need to find the tension in the string when the ball is rotating at the maximum velocity.
**Centripetal Force and Tension Relationship**
The tension in the string is equal to the centripetal force required to keep the ball moving in a circular path. This can be calculated using the equation:
Tension = (mass * velocity^2) / radius
where:
- Tension is the tension in the string
- mass is the mass of the ball (0.25 kg)
- velocity is the velocity of the ball
- radius is the length of the string (1.96 m)
**Calculating the Maximum Tension**
To find the maximum tension, we substitute the maximum velocity into the above equation and solve for tension:
25 N = (0.25 kg * velocity^2) / 1.96 m
Rearranging the equation, we get:
velocity^2 = (25 N * 1.96 m) / 0.25 kg
velocity^2 = 196 N*m / 0.25 kg
velocity^2 = 784 N*m/kg
velocity = √(784 N*m/kg)
velocity ≈ 28 m/s
Therefore, the maximum velocity at which the ball can be rotated without breaking the string is approximately 28 m/s.
Community Answer
A ball of mass 0.25 kg attached to the end of the strings of length 1....
From the point where you hold the the string to the point of attachment of the ball,it is actually the radiusif still confused try to rotate the ball by yourself ,you will understand better.
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A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt?
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A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt?.
A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt?.
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A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt?, a detailed solution for A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt? has been provided alongside types of A ball of mass 0.25 kg attached to the end of the strings of length 1.96m is rotating in a horizontal circle the string will break if tension is more than 25N and what is the maximum velocity? with which the ball can be rotated.in this question why we take r = 1.96 coz v have a full length of string is 1.96 .it's really confused .give me solution .vdout doubt? theory, EduRev gives you an
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