The number of electrons present in one mole of the Azide ion can be determined by considering the molecular formula and the atomic structure of the elements involved.

Atomic Structure of Azide Ion:
The azide ion (N3-) is composed of three nitrogen atoms (N) covalently bonded together with a negative charge. Each nitrogen atom has 7 electrons in its outermost shell and requires 3 additional electrons to complete its octet. Therefore, the azide ion has a total of 3 x (7 + 3) = 30 electrons.

Molar Mass of Azide Ion:
To calculate the number of electrons in one mole of the azide ion, we need to find the molar mass of the ion. The molar mass is the sum of the atomic masses of all the atoms in a molecule.

The atomic mass of nitrogen (N) is approximately 14.01 g/mol. Since the azide ion has three nitrogen atoms, the molar mass of the azide ion is 3 x 14.01 g/mol = 42.03 g/mol.

Avogadro's Number:
Avogadro's number is the number of atoms or molecules present in one mole of a substance. It is approximately 6.022 x 10^23 particles/mol.

Calculating the Number of Electrons:
To find the number of electrons in one mole of the azide ion, we need to multiply the molar mass of the ion by Avogadro's number.

Number of electrons = molar mass x Avogadro's number
= 42.03 g/mol x 6.022 x 10^23 particles/mol

Simplifying the calculation gives us:
Number of electrons ≈ 2.53 x 10^24 electrons

Therefore, the correct option is 2.53N, which represents the number of electrons present in one mole of the azide ion.

Summary:
- The azide ion consists of three nitrogen atoms covalently bonded together with a negative charge.
- Each nitrogen atom requires 3 additional electrons to complete its octet, resulting in a total of 30 electrons in the azide ion.
- The molar mass of the azide ion is 42.03 g/mol.
- Avogadro's number is approximately 6.022 x 10^23 particles/mol.
- Multiplying the molar mass by Avogadro's number gives us the number of electrons in one mole of the azide ion, which is approximately 2.53 x 10^24 electrons.