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Determine the charge that produces an electric field strength of 40 V/cm at a distance of 30cm in vacuum(in 10-8C)
- a)4
- b)2
- c)8
- d)6
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Determine the charge that produces an electric field strength of 40 V/...
Answer: a
Explanation: E = Q/ (4∏εor2)
Q = (4000 X 0.32)/ (9 X 109) = 4 X 10-8 C.
Explanation: E = Q/ (4∏εor2)
Q = (4000 X 0.32)/ (9 X 109) = 4 X 10-8 C.
Most Upvoted Answer
Determine the charge that produces an electric field strength of 40 V/...
Given:
Electric field strength = 40 V/cm
Distance = 30 cm
Charge value = ?
We know that the formula for electric field strength is given by:
E = kQ/r^2
where,
E = electric field strength
k = Coulomb's constant (9 x 10^9 Nm^2/C^2)
Q = charge
r = distance
To find the charge value, we need to rearrange the formula as follows:
Q = Er^2/k
Substituting the given values, we get:
Q = (40 V/cm) x (30 cm)^2 / (9 x 10^9 Nm^2/C^2)
Q = 4 x 10^-8 C
Therefore, the charge that produces an electric field strength of 40 V/cm at a distance of 30 cm in vacuum is 4 x 10^-8 C, which is option A.
Electric field strength = 40 V/cm
Distance = 30 cm
Charge value = ?
We know that the formula for electric field strength is given by:
E = kQ/r^2
where,
E = electric field strength
k = Coulomb's constant (9 x 10^9 Nm^2/C^2)
Q = charge
r = distance
To find the charge value, we need to rearrange the formula as follows:
Q = Er^2/k
Substituting the given values, we get:
Q = (40 V/cm) x (30 cm)^2 / (9 x 10^9 Nm^2/C^2)
Q = 4 x 10^-8 C
Therefore, the charge that produces an electric field strength of 40 V/cm at a distance of 30 cm in vacuum is 4 x 10^-8 C, which is option A.
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Determine the charge that produces an electric field strength of 40 V/...
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