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In how many ways can 10 examination papers be arranged so that the best and the worst papers never come together?
  • a)
    8*9!
  • b)
    8*8!
  • c)
    7*9!
  • d)
    9*8!
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In how many ways can 10 examination papers be arranged so that the bes...
No. of ways in which 10 paper can arranged is 10! Ways.
When the best and the worst papers come together, regarding the two as one paper, we have only 9 papers.
These 9 papers can be arranged in 9! Ways.
And two papers can be arranged themselves in 2! Ways.
No. of arrangement when best and worst paper do not come together,
= 10!- 9!.2! = 9!(10-2) = 8.9!.
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Most Upvoted Answer
In how many ways can 10 examination papers be arranged so that the bes...
Solution:
To find the number of ways of arranging 10 examination papers such that the best and the worst papers never come together, we can use the principle of inclusion and exclusion.

Let A be the set of all arrangements, and let B be the set of arrangements where the best and worst papers are together.

Then, using the principle of inclusion and exclusion, we have:

|A| = 10!
|B| = 9!
|A ∩ B| = 8!

Therefore, the number of arrangements where the best and worst papers never come together is:

|A \ B| = |A| - |B| + |A ∩ B| = 10! - 9! + 8! = 8 × 9!

Hence, the correct option is (a) 8 × 9!.
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In how many ways can 10 examination papers be arranged so that the bes...
A)
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In how many ways can 10 examination papers be arranged so that the best and the worst papers never come together?a)8*9!b)8*8!c)7*9!d)9*8!Correct answer is option 'A'. Can you explain this answer?
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