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A metal crystallizes in face-centered cubic lattice with a lattice parameter of 4.20 Å. The shortest atom to atom contact distance in the lattice is:
  • a)
    4.20 Å
  • b)
    2.97 Å
  • c)
    2.42 Å
  • d)
    2.10 Å
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A metal crystallizes in face-centered cubic lattice with a lattice par...
Explanation:

Given:

Lattice parameter, a = 4.20 Å

Crystal structure = Face-centered cubic lattice


Formula:

In a face-centered cubic lattice, the shortest distance between two atoms is given by:

d = sqrt(2) × a/2


Calculation:

Substituting the given values in the formula:

d = sqrt(2) × 4.20/2

d = 2.97 Å


Therefore, the shortest atom to atom contact distance in the lattice is option B, which is 2.97 Å.
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Community Answer
A metal crystallizes in face-centered cubic lattice with a lattice par...
Laattice parameter = value of edge lengh is given... shortest distance between atom to atom=r+R
we know in fcc (daiganals relation) 2(r+R)= √2 x edge lengh i.e (r+R)= 4.20×√2÷2
r+R)= 2.97 A
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A metal crystallizes in face-centered cubic lattice with a lattice parameter of 4.20 Å. The shortest atom to atom contact distance in the lattice is:a)4.20 Åb)2.97 Åc)2.42 Åd)2.10 ÅCorrect answer is option 'B'. Can you explain this answer?
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