A metal crystallizes in face-centered cubic lattice with a lattice par...
In a face-centered cubic (FCC) lattice, atoms touch along the face diagonal. The face diagonal is equal to √2 times the lattice parameter. Therefore, the shortest atom-to-atom contact distance is calculated as follows: 4.20 Å / √2 = 2.97 Å. Hence, the correct answer is option b.
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A metal crystallizes in face-centered cubic lattice with a lattice par...
Explanation:
Given:
Lattice parameter, a = 4.20 Å
Crystal structure = Face-centered cubic lattice
Formula:
In a face-centered cubic lattice, the shortest distance between two atoms is given by:
d = sqrt(2) × a/2
Calculation:
Substituting the given values in the formula:
d = sqrt(2) × 4.20/2
d = 2.97 Å
Therefore, the shortest atom to atom contact distance in the lattice is option B, which is 2.97 Å.
A metal crystallizes in face-centered cubic lattice with a lattice par...
Laattice parameter = value of edge lengh is given... shortest distance between atom to atom=r+R
we know in fcc (daiganals relation) 2(r+R)= √2 x edge lengh i.e (r+R)= 4.20×√2÷2
r+R)= 2.97 A