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find remainder when 2^31 is divided by 5
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find remainder when 2^31 is divided by 5
Remainder when 2^31 is divided by 5


To find the remainder when 2^31 is divided by 5, we need to understand the concept of modular arithmetic. In modular arithmetic, we divide a number by a modulus and find the remainder. The remainder can only be from 0 to (modulus-1). For example, if we divide 7 by 3, the remainder is 1 because 7 divided by 3 is 2 with a remainder of 1.


Using Modular Exponentiation


We can use modular exponentiation to find the remainder when 2^31 is divided by 5. Modular exponentiation is a technique used to calculate large powers of a number modulo a modulus. We can use the following formula to calculate a^n mod m:


a^n mod m = (a^(n-1) mod m * a) mod m


Using this formula, we can calculate 2^31 mod 5 as follows:


2^31 mod 5 = (2^30 mod 5 * 2) mod 5


We can simplify this expression by calculating 2^30 mod 5 first:


2^30 mod 5 = (2^15 mod 5)^2 mod 5


Again, we can simplify this expression by calculating 2^15 mod 5:


2^15 mod 5 = (2^14 mod 5 * 2) mod 5


We can keep simplifying the expression in this manner until we get down to 2^1 mod 5, which is simply 2 mod 5:


2^1 mod 5 = 2


Using all the previous calculations, we can now calculate 2^31 mod 5 as follows:


2^31 mod 5 = (2^30 mod 5 * 2) mod 5

= ((2^15 mod 5)^2 mod 5 * 2) mod 5

= ((2^14 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5

= (((2^13 mod 5)^2 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5

= (((2^12 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5

= (((2^11 mod 5)^2 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5

= (((2^10 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5)^2 mod 5 * 2) mod 5

= (((2^9 mod 5)^2 mod 5 *
Community Answer
find remainder when 2^31 is divided by 5
Let's look at the first few powers of 22^1 = 22^2 = 42^3=82^4 = 162^5 = 32Does a pattern emerge?2^6 is going to have 4 the unit's place, while 2^7 is going to end with the digit 8.From this, we can conclude that 2^(3,7,11,15,…,31) are all going to have 8 in the unit's place.Since 2^31 ends in 8, the remainder when divided by 5 is 8–5 = 3
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find remainder when 2^31 is divided by 5
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