Since BD = CD,AngleDBC = AngleDCB (Let them be x) Now three sides of triangles sums up to 180.AngleABC + AngleCBA + AngleCAB = 18040 +40+50+x+x = 180solving this, x = 25. in triangle DBC,25+25+AngleDBC = 180angleDBC = 130
Since BD = CD,AngleDBC = AngleDCB (Let them be x)Now three sides of triangles sums up to 180.AngleABC + AngleCBA + AngleCAB = 18040 +40+50+x+x = 180solving this, x = 25.in triangle DBC,25+25+AngleDBC = 180angleDBC = 130
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Since BD = CD,AngleDBC = AngleDCB (Let them be x)Now three sides of triangles sums up to 180.AngleABC + AngleCBA + AngleCAB = 18040 +40+50+x+x = 180solving this, x = 25.in triangle DBC,25+25+AngleDBC = 180angleDBC = 130
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