CA Foundation Exam > CA Foundation Questions > If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n...
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If n1+n2P2 = 132, n1–n2P2 = 30 then,
- a)n1=6,n2=6
- b)n1 = 10, n2 = 2
- c)n1 = 9, n2 = 3
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2...
Most Upvoted Answer
If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2...
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If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2...
Given:
n1n2P2 = 132
n1n2P2/P2 = n1n2 = 30
To find: n1 and n2
Solution:
Prime factorization of 132: 2 x 2 x 3 x 11
Prime factorization of 30: 2 x 3 x 5
We can write n1n2P2 as (n1 x P)(n2 x P) = n1n2P^2
Substituting the given values, we get:
n1n2P^2 = 132
n1n2 = 30
Therefore, P^2 = 132/30 = 44/10 = 22/5
We can write P^2 as (n1n2P^2)/(n1n2) = (n1 x n2 x P^2)/(n1n2) = P^2/(n1n2/P)
Substituting the given values, we get:
P^2/(n1n2/P) = 22/5
Simplifying, we get:
P = 2, n1n2/P = 15
Now, we know that n1n2 = 30 and n1n2/P = 15
Therefore, P = 2, n1n2 = 30, n1n2/P = 15
We can now substitute these values in n1n2P^2 = 132 to get:
n1n2 x 4 = 132
n1n2 = 33
We need to find two numbers whose product is 33 and whose sum is even (because P = 2). The only such pair is 9 and 3. Therefore, n1 = 9 and n2 = 3.
Hence, the correct answer is option C, n1 = 9 and n2 = 3.
n1n2P2 = 132
n1n2P2/P2 = n1n2 = 30
To find: n1 and n2
Solution:
Prime factorization of 132: 2 x 2 x 3 x 11
Prime factorization of 30: 2 x 3 x 5
We can write n1n2P2 as (n1 x P)(n2 x P) = n1n2P^2
Substituting the given values, we get:
n1n2P^2 = 132
n1n2 = 30
Therefore, P^2 = 132/30 = 44/10 = 22/5
We can write P^2 as (n1n2P^2)/(n1n2) = (n1 x n2 x P^2)/(n1n2) = P^2/(n1n2/P)
Substituting the given values, we get:
P^2/(n1n2/P) = 22/5
Simplifying, we get:
P = 2, n1n2/P = 15
Now, we know that n1n2 = 30 and n1n2/P = 15
Therefore, P = 2, n1n2 = 30, n1n2/P = 15
We can now substitute these values in n1n2P^2 = 132 to get:
n1n2 x 4 = 132
n1n2 = 33
We need to find two numbers whose product is 33 and whose sum is even (because P = 2). The only such pair is 9 and 3. Therefore, n1 = 9 and n2 = 3.
Hence, the correct answer is option C, n1 = 9 and n2 = 3.
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If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer?
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If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer?.
If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer?.
Solutions for If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for CA Foundation.
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If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of If n1+n2P2 = 132, n1–n2P2 = 30 then,a)n1=6,n2=6b)n1 = 10, n2 = 2c)n1 = 9, n2 = 3d)none of theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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