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In limit state design method, the moment of resistance for a balanced section using M20 grade concrete and HYSD steel of grade Fe 415 is given by Mu,lim = Kbd2, what is the value of K?
  • a)
    2.98
  • b)
    2.76
  • c)
    1.19
  • d)
    0.89
Correct answer is option 'B'. Can you explain this answer?
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In limit state design method, the moment of resistance for a balanced ...
Mu limit = 0.138 fck bd^2 for fe415  grade steel
= 0.138 x 20 x bd^2
= 2.776 bd^2
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In limit state design method, the moment of resistance for a balanced ...
Limit State Design Method and Moment of Resistance

Limit State Design Method is a design approach used in structural engineering which involves designing a structure to withstand the maximum loads it may encounter during its lifetime while also ensuring safety and serviceability. Moment of Resistance is a key parameter in the design of a structural element, which represents the maximum bending moment a section can withstand before failure occurs.

Formula for Moment of Resistance

The formula for Moment of Resistance for a balanced section using M20 grade concrete and HYSD steel of grade Fe 415 is given as:

Mu,lim = Kbd2

where,

Mu,lim = Limiting moment of resistance

K = Coefficient of resistance

b = Width of the cross-section

d = Effective depth of the cross-section

Calculation of Coefficient of Resistance

To calculate the coefficient of resistance (K), we need to know the characteristics of the concrete and steel being used. In this case, we are using M20 grade concrete and HYSD steel of grade Fe 415. The value of K for this combination can be calculated as follows:

- K = 0.36(1 - (fy/1400))(fck/25)^(1/3)

where,

fy = Yield strength of steel (Fe 415) = 415 N/mm^2

fck = Characteristic compressive strength of concrete (M20) = 20 N/mm^2

Substituting the values in the above equation, we get:

K = 0.36(1 - (415/1400))(20/25)^(1/3)

K = 0.36(0.7036)(0.8)^(1/3)

K = 0.276

Therefore, the value of K is 0.276, which is option B.
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In limit state design method, the moment of resistance for a balanced section using M20 grade concrete and HYSD steel of grade Fe 415 is given by Mu,lim = Kbd2, what is the value of K?a)2.98b)2.76c)1.19d)0.89Correct answer is option 'B'. Can you explain this answer?
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