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A body of mass 2kg has an initial velocity of 3m/s along OE and it is subjected to a force of 4 newtons in a direction perpendicular to OE. The distance of body from O after 4 seconds will be ?
Verified Answer
A body of mass 2kg has an initial velocity of 3m/s along OE and it is ...
Along OE,
Velocity, VOE = 3 m/s
Since, the applied force is perpendicular to OE so the velocity VOE will be constant.
So, displacement along OE in 4 s is, SOE = 3 x 4 = 12 m
Along OF,
Force applied, F = 4 N
Mass of the body, m = 2 kg
So, acceleration, a = F/m = 2 m/s^2
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Most Upvoted Answer
A body of mass 2kg has an initial velocity of 3m/s along OE and it is ...
Given data:
- Mass of the body (m) = 2 kg
- Initial velocity (u) = 3 m/s along OE
- Force (F) = 4 N in a direction perpendicular to OE
- Time (t) = 4 s
Explanation:
1. The force acting on the body:
The force acting on the body is given by Newton's second law of motion as:
F = ma
Where,
F = force (4 N)
m = mass (2 kg)
a = acceleration
We can rearrange the equation to get the acceleration as:
a = F/m
Substituting the given values, we have:
a = 4 N / 2 kg
a = 2 m/s²
2. Displacement of the body:
The displacement of the body can be calculated using the equation of motion:
s = ut + (1/2)at²
Where,
s = displacement
u = initial velocity (3 m/s)
t = time (4 s)
a = acceleration (2 m/s²)
Substituting the values, we have:
s = (3 m/s)(4 s) + (1/2)(2 m/s²)(4 s)²
s = 12 m + (1/2)(2 m/s²)(16 s²)
s = 12 m + (1/2)(2 m/s²)(256 s²)
s = 12 m + (1/2)(512 m)
s = 12 m + 256 m
s = 268 m
3. Distance of the body from O:
The distance of the body from O is the magnitude of the displacement. Therefore, the distance of the body from O after 4 seconds will be 268 meters.
Summary:
- The force acting on the body is 4 N.
- Using Newton's second law, we can find the acceleration as 2 m/s².
- Using the equation of motion, we can calculate the displacement of the body as 268 meters.
- Therefore, the distance of the body from O after 4 seconds will be 268 meters.
- Mass of the body (m) = 2 kg
- Initial velocity (u) = 3 m/s along OE
- Force (F) = 4 N in a direction perpendicular to OE
- Time (t) = 4 s
Explanation:
1. The force acting on the body:
The force acting on the body is given by Newton's second law of motion as:
F = ma
Where,
F = force (4 N)
m = mass (2 kg)
a = acceleration
We can rearrange the equation to get the acceleration as:
a = F/m
Substituting the given values, we have:
a = 4 N / 2 kg
a = 2 m/s²
2. Displacement of the body:
The displacement of the body can be calculated using the equation of motion:
s = ut + (1/2)at²
Where,
s = displacement
u = initial velocity (3 m/s)
t = time (4 s)
a = acceleration (2 m/s²)
Substituting the values, we have:
s = (3 m/s)(4 s) + (1/2)(2 m/s²)(4 s)²
s = 12 m + (1/2)(2 m/s²)(16 s²)
s = 12 m + (1/2)(2 m/s²)(256 s²)
s = 12 m + (1/2)(512 m)
s = 12 m + 256 m
s = 268 m
3. Distance of the body from O:
The distance of the body from O is the magnitude of the displacement. Therefore, the distance of the body from O after 4 seconds will be 268 meters.
Summary:
- The force acting on the body is 4 N.
- Using Newton's second law, we can find the acceleration as 2 m/s².
- Using the equation of motion, we can calculate the displacement of the body as 268 meters.
- Therefore, the distance of the body from O after 4 seconds will be 268 meters.
Community Answer
A body of mass 2kg has an initial velocity of 3m/s along OE and it is ...
It's 20 metre
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A body of mass 2kg has an initial velocity of 3m/s along OE and it is subjected to a force of 4 newtons in a direction perpendicular to OE. The distance of body from O after 4 seconds will be ?
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A body of mass 2kg has an initial velocity of 3m/s along OE and it is subjected to a force of 4 newtons in a direction perpendicular to OE. The distance of body from O after 4 seconds will be ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body of mass 2kg has an initial velocity of 3m/s along OE and it is subjected to a force of 4 newtons in a direction perpendicular to OE. The distance of body from O after 4 seconds will be ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 2kg has an initial velocity of 3m/s along OE and it is subjected to a force of 4 newtons in a direction perpendicular to OE. The distance of body from O after 4 seconds will be ?.
A body of mass 2kg has an initial velocity of 3m/s along OE and it is subjected to a force of 4 newtons in a direction perpendicular to OE. The distance of body from O after 4 seconds will be ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body of mass 2kg has an initial velocity of 3m/s along OE and it is subjected to a force of 4 newtons in a direction perpendicular to OE. The distance of body from O after 4 seconds will be ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 2kg has an initial velocity of 3m/s along OE and it is subjected to a force of 4 newtons in a direction perpendicular to OE. The distance of body from O after 4 seconds will be ?.
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