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If a bullet of mass 5 gm moving with velocity 100 m/sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block is
- a)8300 N
- b)417 N
- c)830 N
- d)Zero
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
If a bullet of mass 5 gm moving with velocity 100 m/sec, penetrates th...
Here too we use equation of motion
v^2 = u^2 + 2as
2as = v^2 - u^2
2 x a x (6/100) = 0 - (100)^2
12a / 100 = - 10000
a = -1000000 / 12 m/s^2
This is the average retardation of the bullet
Avg force F = m a
= (5/1000) x 1000000 / 12 = 416.66 N
approx 417 newton
Most Upvoted Answer
If a bullet of mass 5 gm moving with velocity 100 m/sec, penetrates th...
Given:
Mass of bullet, m = 5 g = 0.005 kg
Initial velocity of bullet, u = 100 m/s
Distance penetrated by bullet, s = 6 cm = 0.06 m
We can use the formula for work done by an external force, W = F × s, to find the average force exerted by the bullet on the wooden block.
Work done by bullet on the block:
W = 0.5 × m × u^2
W = 0.5 × 0.005 × (100)^2
W = 250 J
The negative of this work done is the work done by the block on the bullet, which is the force acting on the bullet in the opposite direction.
Force exerted by block on bullet:
F = -W/s
F = -250/0.06
F = -4166.67 N
Since the force is negative, we take the magnitude to get the average force exerted by the bullet on the block.
Average force exerted by bullet on block:
F = 4166.67 N ≈ 417 N
Therefore, the correct option is (B) 417 N.
Mass of bullet, m = 5 g = 0.005 kg
Initial velocity of bullet, u = 100 m/s
Distance penetrated by bullet, s = 6 cm = 0.06 m
We can use the formula for work done by an external force, W = F × s, to find the average force exerted by the bullet on the wooden block.
Work done by bullet on the block:
W = 0.5 × m × u^2
W = 0.5 × 0.005 × (100)^2
W = 250 J
The negative of this work done is the work done by the block on the bullet, which is the force acting on the bullet in the opposite direction.
Force exerted by block on bullet:
F = -W/s
F = -250/0.06
F = -4166.67 N
Since the force is negative, we take the magnitude to get the average force exerted by the bullet on the block.
Average force exerted by bullet on block:
F = 4166.67 N ≈ 417 N
Therefore, the correct option is (B) 417 N.
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Community Answer
If a bullet of mass 5 gm moving with velocity 100 m/sec, penetrates th...
K.E = F × displacement 1/2m v^2 = F× d 1/2 × 5 ×
10 ^-3 ×10^4 = F × 6 × 10^-2 solving this we get F = 417.
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If a bullet of mass 5 gm moving with velocity 100 m/sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block isa)8300 Nb)417 Nc)830 Nd)ZeroCorrect answer is option 'B'. Can you explain this answer?
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