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Charcoal (1 g) of surface area 100 m2 per gram, adsorbs 60 mg of acetic from an aqueous solution at 25°C and 1 atmosphere pressure. The number of moles of acetic acid adsorbed per cm2 of charcoal surface is:
  • a)
    10–2
  • b)
    10–6
  • c)
    10–5
  • d)
    10–9
Correct answer is option 'B'. Can you explain this answer?
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Calculation of moles of acetic acid adsorbed per cm2 of charcoal surface

Given information:
- Surface area of charcoal = 100 m2 per gram = 10^4 cm2 per gram
- Amount of charcoal used = 1 g
- Amount of acetic acid adsorbed = 60 mg
- Temperature = 25°C
- Pressure = 1 atm

Conversion of units:
- 60 mg = 0.06 g
- Temperature = 298 K
- Pressure = 1 atm = 101.3 kPa

Calculation of moles of acetic acid adsorbed:
- The molar mass of acetic acid (CH3COOH) = 60.05 g/mol
- Number of moles of acetic acid adsorbed = (0.06 g) / (60.05 g/mol) = 0.0009992 mol

Calculation of surface area of charcoal used:
- Surface area of charcoal used = (1 g) x (10^4 cm2 per gram) = 10^4 cm2

Calculation of moles of acetic acid adsorbed per cm2 of charcoal surface:
- Moles of acetic acid adsorbed per cm2 of charcoal surface = (0.0009992 mol) / (10^4 cm2) = 1.00 x 10^-7 mol/cm2

Therefore, the correct option is B) 10^6, which represents 1.00 x 10^-7 mol/cm2 in scientific notation.
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Charcoal (1 g) of surface area 100 m2 per gram, adsorbs 60 mg of acetic from an aqueous solution at 25°C and 1 atmosphere pressure. The number of moles of acetic acid adsorbed per cm2 of charcoal surface is:a)10–2b)10–6c)10–5d)10–9Correct answer is option 'B'. Can you explain this answer?
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