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Charcoal (1 gram) of surface area 100 m2 per gram, absorbs 60 mg of acetic acid from an aqueous solution at 25°C and 1 atmosphere pressure. The number of moles of acetic acid adsorbed per cm2 of charcoal surface is:
- a)10–2
- b)10–6
- c)10–5
- d)10–9
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Charcoal (1 gram) of surface area 100 m2 per gram, absorbs 60 mg of ac...
Molar mass of acetic acid is 60 g.mole^-1
i.e. 60 g = (60×1000 mg) of acetic acid contains 1 mole
so, 60 mg of acetic acid contains [{1/(60×1000 mg)}×60mg] moles
= 10^-3 moles
Now, surface area of 100 m² per gram i.e. (100×10⁴) cm² per gram charcoal can adsorb 60 mg or 10^-3 moles of acetic acid
therefore, the number of moles of acetic acid adsorbed per cm² of charcoal surface would be = {10^-3/(100×10⁴)} moles = 10^-9 moles
i.e. 60 g = (60×1000 mg) of acetic acid contains 1 mole
so, 60 mg of acetic acid contains [{1/(60×1000 mg)}×60mg] moles
= 10^-3 moles
Now, surface area of 100 m² per gram i.e. (100×10⁴) cm² per gram charcoal can adsorb 60 mg or 10^-3 moles of acetic acid
therefore, the number of moles of acetic acid adsorbed per cm² of charcoal surface would be = {10^-3/(100×10⁴)} moles = 10^-9 moles
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Community Answer
Charcoal (1 gram) of surface area 100 m2 per gram, absorbs 60 mg of ac...
Given:
Charcoal surface area = 100 m^2/g
Amount of charcoal = 1 g
Amount of acetic acid absorbed = 60 mg
To find:
Number of moles of acetic acid adsorbed per cm^2 of charcoal surface
Solution:
Step 1: Convert the surface area of charcoal to cm^2/g
1 m^2 = 10,000 cm^2
So, surface area of charcoal = 100 m^2/g = 100 × 10,000 cm^2/g = 1,000,000 cm^2/g
Step 2: Convert the amount of acetic acid absorbed to moles
1 mole of acetic acid = molar mass of acetic acid = 60 g/mol
1 g of acetic acid = 1/60 moles = 0.0167 moles
60 mg of acetic acid = 0.060 g
So, amount of acetic acid absorbed = 0.060 g = 0.060/60 = 0.001 moles
Step 3: Calculate the number of moles of acetic acid adsorbed per cm^2 of charcoal surface
Number of moles of acetic acid adsorbed per cm^2 of charcoal surface = (moles of acetic acid absorbed) / (surface area of charcoal in cm^2)
= 0.001 moles / 1,000,000 cm^2 = 1 × 10^(-9) moles/cm^2
Step 4: Convert the number of moles to scientific notation
1 × 10^(-9) = 1 × 10^(-9) × 10^9 / 10^9 = 10^0 × 10^9 / 10^9
= 10^(0+9-9) = 10^0 = 1
Final Answer:
The number of moles of acetic acid adsorbed per cm^2 of charcoal surface is 1.
Charcoal surface area = 100 m^2/g
Amount of charcoal = 1 g
Amount of acetic acid absorbed = 60 mg
To find:
Number of moles of acetic acid adsorbed per cm^2 of charcoal surface
Solution:
Step 1: Convert the surface area of charcoal to cm^2/g
1 m^2 = 10,000 cm^2
So, surface area of charcoal = 100 m^2/g = 100 × 10,000 cm^2/g = 1,000,000 cm^2/g
Step 2: Convert the amount of acetic acid absorbed to moles
1 mole of acetic acid = molar mass of acetic acid = 60 g/mol
1 g of acetic acid = 1/60 moles = 0.0167 moles
60 mg of acetic acid = 0.060 g
So, amount of acetic acid absorbed = 0.060 g = 0.060/60 = 0.001 moles
Step 3: Calculate the number of moles of acetic acid adsorbed per cm^2 of charcoal surface
Number of moles of acetic acid adsorbed per cm^2 of charcoal surface = (moles of acetic acid absorbed) / (surface area of charcoal in cm^2)
= 0.001 moles / 1,000,000 cm^2 = 1 × 10^(-9) moles/cm^2
Step 4: Convert the number of moles to scientific notation
1 × 10^(-9) = 1 × 10^(-9) × 10^9 / 10^9 = 10^0 × 10^9 / 10^9
= 10^(0+9-9) = 10^0 = 1
Final Answer:
The number of moles of acetic acid adsorbed per cm^2 of charcoal surface is 1.
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Charcoal (1 gram) of surface area 100 m2 per gram, absorbs 60 mg of acetic acid from an aqueous solution at 25°C and 1 atmosphere pressure. The number of moles of acetic acid adsorbed per cm2 of charcoal surface is:a)10–2b)10–6c)10–5d)10–9Correct answer is option 'D'. Can you explain this answer?
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Charcoal (1 gram) of surface area 100 m2 per gram, absorbs 60 mg of acetic acid from an aqueous solution at 25°C and 1 atmosphere pressure. The number of moles of acetic acid adsorbed per cm2 of charcoal surface is:a)10–2b)10–6c)10–5d)10–9Correct answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Charcoal (1 gram) of surface area 100 m2 per gram, absorbs 60 mg of acetic acid from an aqueous solution at 25°C and 1 atmosphere pressure. The number of moles of acetic acid adsorbed per cm2 of charcoal surface is:a)10–2b)10–6c)10–5d)10–9Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Charcoal (1 gram) of surface area 100 m2 per gram, absorbs 60 mg of acetic acid from an aqueous solution at 25°C and 1 atmosphere pressure. The number of moles of acetic acid adsorbed per cm2 of charcoal surface is:a)10–2b)10–6c)10–5d)10–9Correct answer is option 'D'. Can you explain this answer?.
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