3g of activated charcoal was added to 50 ml of acetic acid solution (0...
To find the amount of acetic acid adsorbed per gram of charcoal, we need to calculate the mass of acetic acid adsorbed by the activated charcoal and divide it by the mass of charcoal used.
The initial concentration of acetic acid is 0.06 M, and after adsorption, the final concentration is 0.042 M. The difference between the initial and final concentrations represents the amount of acetic acid adsorbed by the activated charcoal.
0.06 M - 0.042 M = 0.018 M
Now we need to find the mass of acetic acid (in grams) that was adsorbed by the activated charcoal. We can use the equation: molarity x volume = moles
0.018 M x 50 ml = 0.9 moles
Now, we can find mass of acetic acid adsorbed by mass = moles x molar mass
mass = 0.9 moles x 60 g/mol = 54 g
Now we need to divide the mass of acetic acid adsorbed by the mass of activated charcoal used:
54 g / 3 g = 18 g/g
Therefore, the amount of acetic acid adsorbed per gram of charcoal is 18 mg, So the correct answer is 2.