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Molybdenum crystallizes in a bcc-structure with unit cell dimensions of 0.314 nm. Considering the atomic mass of molybdenum to be 96, its density (in kg m–3) is in the range of:
  • a)
    8000-10000
  • b)
    10000-10200
  • c)
    10000-10300
  • d)
    10000-10500
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Molybdenum crystallizes in a bcc-structure with unit cell dimensions o...
We know that d = (zM) /(Na)*(a³) and
z = 2 for bcc

Substituting for M (96 g/mol), Na (Avogadro number), and a (0.314nm),

We get d = 10298 kg/m³
Hence, option c is correct.
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Community Answer
Molybdenum crystallizes in a bcc-structure with unit cell dimensions o...
Molybdenum Density Calculation

Given:
- Crystal structure of molybdenum: bcc
- Unit cell dimensions: 0.314 nm
- Atomic mass of molybdenum: 96

To find: Density of molybdenum in kg/m3

Solution:

1. Calculate the volume of the unit cell
- Volume of a bcc unit cell = (4 * r/√3)^3
- Here, r = 0.314 nm/2 = 0.157 nm (radius is half of the unit cell dimension)
- Volume of the unit cell = (4 * 0.157 nm/√3)^3
- Volume of the unit cell = 1.787 x 10^-29 m^3

2. Calculate the number of atoms in the unit cell
- There are 2 atoms in a bcc unit cell
- Therefore, number of atoms in the unit cell = 2

3. Calculate the mass of one unit cell
- Mass of one unit cell = number of atoms x atomic mass
- Mass of one unit cell = 2 x 96 g/mol
- Mass of one unit cell = 192 g/mol

4. Convert the mass of one unit cell to kg
- Mass of one unit cell = 192 g/mol x 1 kg/1000 g
- Mass of one unit cell = 0.192 kg

5. Calculate the density of molybdenum
- Density = mass/volume
- Density = 0.192 kg/1.787 x 10^-29 m^3
- Density = 1.075 x 10^4 kg/m3

Answer: The density of molybdenum is in the range of 10000-10300 kg/m3, which is option C.
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