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A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?
- a)10 km
- b)13 km
- c)15 km
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A man walks 2 km towards North. Then he turns to East and walks 10 km....
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A man walks 2 km towards North. Then he turns to East and walks 10 km....
Understanding the Movement:
The man first walks 2 km towards North, then turns East and walks 10 km, then turns North again and walks 3 km, and finally turns East and walks 2 km.
Finding the Distance from Starting Point:
To find the distance from the starting point, we need to calculate the net displacement in both the North-South and East-West directions.
- In the North-South direction, the man moves 2 km North and then 3 km North, so the net displacement is 2 km + 3 km = 5 km North.
- In the East-West direction, the man moves 10 km East and then 2 km East, so the net displacement is 10 km + 2 km = 12 km East.
Applying Pythagoras Theorem:
Now, we can use Pythagoras theorem to find the distance from the starting point:
Distance = √(North-South displacement)^2 + (East-West displacement)^2
Distance = √(5 km)^2 + (12 km)^2
Distance = √(25 + 144) km
Distance = √169 km
Distance = 13 km
Therefore, the man is 13 km away from the starting point. Hence, the correct answer is option B.
The man first walks 2 km towards North, then turns East and walks 10 km, then turns North again and walks 3 km, and finally turns East and walks 2 km.
Finding the Distance from Starting Point:
To find the distance from the starting point, we need to calculate the net displacement in both the North-South and East-West directions.
- In the North-South direction, the man moves 2 km North and then 3 km North, so the net displacement is 2 km + 3 km = 5 km North.
- In the East-West direction, the man moves 10 km East and then 2 km East, so the net displacement is 10 km + 2 km = 12 km East.
Applying Pythagoras Theorem:
Now, we can use Pythagoras theorem to find the distance from the starting point:
Distance = √(North-South displacement)^2 + (East-West displacement)^2
Distance = √(5 km)^2 + (12 km)^2
Distance = √(25 + 144) km
Distance = √169 km
Distance = 13 km
Therefore, the man is 13 km away from the starting point. Hence, the correct answer is option B.
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A man walks 2 km towards North. Then he turns to East and walks 10 km....
Ans b
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A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?a)10 kmb)13kmc)15kmd)None of theseCorrect answer is option 'B'. Can you explain this answer?
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