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Divide 56 into two parts such that three times the first part exceeds one third of the second by 48 the parts are.
- a)(20,36)
- b)(25,31)
- c)(24,32)
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Divide 56 into two parts such that three times the first part exceeds ...
Divided 56 into two parts such that three times the first part exceed one third of second by 48.
Part one:: x
Part two:: 56-x
Equation:
3(56-x)-(1/3)x = 48
168 - 3x - (1/3)x = 48
-10/3 x = - 120
(1/3)x = 12
x = 36
56-x = 20
Most Upvoted Answer
Divide 56 into two parts such that three times the first part exceeds ...
Given information:
- Two parts of a number, let's say x and y
- 56 is the total number, so x + y = 56
- Three times the first part exceeds one third of the second by 48, which can be written as 3x = (1/3)y + 48
Solving for x and y:
- Multiply both sides of the second equation by 3 to eliminate the fraction: 9x = y + 144
- Substitute y in the first equation with 9x - 144: x + (9x - 144) = 56
- Simplify: 10x - 144 = 56
- Add 144 to both sides: 10x = 200
- Divide by 10: x = 20
- Substitute x back in the first equation to find y: 20 + y = 56, so y = 36
Therefore, the two parts of the number are 20 and 36, which corresponds to option A.
- Two parts of a number, let's say x and y
- 56 is the total number, so x + y = 56
- Three times the first part exceeds one third of the second by 48, which can be written as 3x = (1/3)y + 48
Solving for x and y:
- Multiply both sides of the second equation by 3 to eliminate the fraction: 9x = y + 144
- Substitute y in the first equation with 9x - 144: x + (9x - 144) = 56
- Simplify: 10x - 144 = 56
- Add 144 to both sides: 10x = 200
- Divide by 10: x = 20
- Substitute x back in the first equation to find y: 20 + y = 56, so y = 36
Therefore, the two parts of the number are 20 and 36, which corresponds to option A.
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Community Answer
Divide 56 into two parts such that three times the first part exceeds ...
Let the first part be x
and
two parts of 56 be (56-x) eqn (1)
thrice of first part be 3x eqn (2)
1/3rd of 2nd part = 1/3 × (56-x) eqn(3)
Then eqn(2) - eqn(3) = 48
3x - (56 - x ) / 3 = 48
(9x - 56 + x ) / 3 = 48
9x -56 +x = 48×3
10x - 56 = 144
10x = 144 + 56
10x = 200
x = 20
put x = 20 in eqn (1)
then we get 56 - x
= 56-20 = 36
then the nmbrs are (20, 36)
and
two parts of 56 be (56-x) eqn (1)
thrice of first part be 3x eqn (2)
1/3rd of 2nd part = 1/3 × (56-x) eqn(3)
Then eqn(2) - eqn(3) = 48
3x - (56 - x ) / 3 = 48
(9x - 56 + x ) / 3 = 48
9x -56 +x = 48×3
10x - 56 = 144
10x = 144 + 56
10x = 200
x = 20
put x = 20 in eqn (1)
then we get 56 - x
= 56-20 = 36
then the nmbrs are (20, 36)
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Divide 56 into two parts such that three times the first part exceeds one third of the second by 48 the parts are.a)(20,36)b)(25,31)c)(24,32)d)none of theseCorrect answer is option 'A'. Can you explain this answer?
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Divide 56 into two parts such that three times the first part exceeds one third of the second by 48 the parts are.a)(20,36)b)(25,31)c)(24,32)d)none of theseCorrect answer is option 'A'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Divide 56 into two parts such that three times the first part exceeds one third of the second by 48 the parts are.a)(20,36)b)(25,31)c)(24,32)d)none of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Divide 56 into two parts such that three times the first part exceeds one third of the second by 48 the parts are.a)(20,36)b)(25,31)c)(24,32)d)none of theseCorrect answer is option 'A'. Can you explain this answer?.
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