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An ac voltmeter using full wave rectification and having sinusoidal input has an ac sensitivity equal to
- a)1.414 times dc sensitivity
- b)dc sensitivity
- c)0.90 times dc sensitivity
- d)0.707 times dc sensitivity
Correct answer is option 'C'. Can you explain this answer?
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An ac voltmeter using full wave rectification and having sinusoidal in...
For full-wave rectifier type of instruments Vavg = 0.9V where V = Vm/2 .
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An ac voltmeter using full wave rectification and having sinusoidal in...
Explanation:
AC sensitivity is defined as the ratio of the change in the output voltage of the voltmeter to the change in the input voltage of the voltmeter. For an AC voltmeter using full wave rectification and having a sinusoidal input, the AC sensitivity can be calculated as follows:
AC Sensitivity = (Change in Output voltage / Change in Input Voltage)
Full wave rectification involves rectifying both the positive and negative halves of the input waveform, resulting in a pulsating DC waveform with a frequency twice that of the input waveform. This pulsating DC waveform is then filtered using a capacitor to produce a DC voltage that is proportional to the RMS value of the input waveform.
DC sensitivity is defined as the ratio of the change in the output voltage of the voltmeter to the change in the input voltage of the voltmeter for a DC input.
For an AC voltmeter using full wave rectification and having a sinusoidal input, the AC sensitivity can be related to the DC sensitivity as follows:
AC Sensitivity = (Change in Output voltage / Change in Input Voltage)
= (Peak Output Voltage / RMS Input Voltage)
DC Sensitivity = (Change in Output voltage / Change in Input Voltage)
= (Output Voltage / Input Voltage)
Substituting the RMS value of the sinusoidal input voltage for the input voltage and the peak value of the rectified output voltage for the output voltage, we get:
AC Sensitivity = (Peak Output Voltage / RMS Input Voltage)
= (1.414 x RMS Output Voltage / RMS Input Voltage)
= 1.414 x (RMS Output Voltage / RMS Input Voltage)
DC Sensitivity = (Output Voltage / Input Voltage)
= (RMS Output Voltage / RMS Input Voltage)
Therefore, the ratio of AC sensitivity to DC sensitivity can be calculated as:
AC Sensitivity / DC Sensitivity = (1.414 x RMS Output Voltage / RMS Input Voltage) / (RMS Output Voltage / RMS Input Voltage)
= 1.414
Hence, the AC sensitivity of an AC voltmeter using full wave rectification and having a sinusoidal input is 0.90 (i.e. 1.414 / 1.57) times the DC sensitivity.
AC sensitivity is defined as the ratio of the change in the output voltage of the voltmeter to the change in the input voltage of the voltmeter. For an AC voltmeter using full wave rectification and having a sinusoidal input, the AC sensitivity can be calculated as follows:
AC Sensitivity = (Change in Output voltage / Change in Input Voltage)
Full wave rectification involves rectifying both the positive and negative halves of the input waveform, resulting in a pulsating DC waveform with a frequency twice that of the input waveform. This pulsating DC waveform is then filtered using a capacitor to produce a DC voltage that is proportional to the RMS value of the input waveform.
DC sensitivity is defined as the ratio of the change in the output voltage of the voltmeter to the change in the input voltage of the voltmeter for a DC input.
For an AC voltmeter using full wave rectification and having a sinusoidal input, the AC sensitivity can be related to the DC sensitivity as follows:
AC Sensitivity = (Change in Output voltage / Change in Input Voltage)
= (Peak Output Voltage / RMS Input Voltage)
DC Sensitivity = (Change in Output voltage / Change in Input Voltage)
= (Output Voltage / Input Voltage)
Substituting the RMS value of the sinusoidal input voltage for the input voltage and the peak value of the rectified output voltage for the output voltage, we get:
AC Sensitivity = (Peak Output Voltage / RMS Input Voltage)
= (1.414 x RMS Output Voltage / RMS Input Voltage)
= 1.414 x (RMS Output Voltage / RMS Input Voltage)
DC Sensitivity = (Output Voltage / Input Voltage)
= (RMS Output Voltage / RMS Input Voltage)
Therefore, the ratio of AC sensitivity to DC sensitivity can be calculated as:
AC Sensitivity / DC Sensitivity = (1.414 x RMS Output Voltage / RMS Input Voltage) / (RMS Output Voltage / RMS Input Voltage)
= 1.414
Hence, the AC sensitivity of an AC voltmeter using full wave rectification and having a sinusoidal input is 0.90 (i.e. 1.414 / 1.57) times the DC sensitivity.
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An ac voltmeter using full wave rectification and having sinusoidal input has an ac sensitivity equal toa)1.414 times dc sensitivityb)dc sensitivityc)0.90 times dc sensitivityd)0.707 times dc sensitivityCorrect answer is option 'C'. Can you explain this answer?
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