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A dc shunt generator has full-load voltage regulation of 10% at rated speed of 1000 rpm. If it is now driven at 1250 rpm, then its voltage regulation at full load would
a) Be less than 10%
b) Be more than 10%
c) Remain unchanged
d) Be 12.5%
Correct answer is option 'B'. Can you explain this answer?
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A dc shunt generator has full-load voltage regulation of 10% at rated ...
Explanation:

Voltage regulation of a generator is defined as the change in terminal voltage from no load to full load, expressed as a percentage of full-load voltage. It is given by the formula:

% Voltage Regulation = (VNL - VFL)/VFL x 100

Where VNL is the no-load voltage and VFL is the full-load voltage.

Given, the full-load voltage regulation of a DC shunt generator at rated speed of 1000 rpm is 10%. This means that when the generator is operating at full load, the voltage drops by 10% from the no-load voltage.

Now, if the generator is driven at 1250 rpm, we can assume that the armature current will increase due to the increase in speed. This will result in an increase in the armature reaction and a decrease in the field flux. As a result, the generated voltage will decrease.

Therefore, the voltage regulation at full load would be more than 10%. This is because the voltage drop from no-load to full load will be higher due to the decrease in generated voltage.

Hence, the correct answer is option 'B'.
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A dc shunt generator has full-load voltage regulation of 10% at rated speed of 1000 rpm. If it is now driven at 1250 rpm, then its voltage regulation at full load woulda) Be less than 10%b) Be more than 10%c) Remain unchangedd) Be 12.5%Correct answer is option 'B'. Can you explain this answer?
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