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If law of conservation of mass was to hold true,then 20.8 g of BaCl^2,on reaction with 9.8 g of H^2SO^4 will produce 7.3 g of HCl and ____of BaSO^4?
Verified Answer
If law of conservation of mass was to hold true,then 20.8 g of BaCl^2,...
Let mass of BaSO4 = x
20.8 + 9.8 = 30.6
30.6 - 7.3 =23.3 gm
mass of BaSO4 = 23.3 gm

Law of conservation of mass is working here.
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Most Upvoted Answer
If law of conservation of mass was to hold true,then 20.8 g of BaCl^2,...
According to law of conservation of mass total mass of reactant should be equal to total mass of product.
Mass of BASO4 =20.8+9.8-7.3
                                =23.3g
Community Answer
If law of conservation of mass was to hold true,then 20.8 g of BaCl^2,...
As per law of conservation of mass 20.8g+9.8g=7.2g+(mass of BaSO4)So mass of BaSO4=23.3g
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If law of conservation of mass was to hold true,then 20.8 g of BaCl^2,on reaction with 9.8 g of H^2SO^4 will produce 7.3 g of HCl and ____of BaSO^4?
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If law of conservation of mass was to hold true,then 20.8 g of BaCl^2,on reaction with 9.8 g of H^2SO^4 will produce 7.3 g of HCl and ____of BaSO^4? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If law of conservation of mass was to hold true,then 20.8 g of BaCl^2,on reaction with 9.8 g of H^2SO^4 will produce 7.3 g of HCl and ____of BaSO^4? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If law of conservation of mass was to hold true,then 20.8 g of BaCl^2,on reaction with 9.8 g of H^2SO^4 will produce 7.3 g of HCl and ____of BaSO^4?.
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