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Consider AB2 molecule Calculate % s-character in A—B bond:
    Correct answer is '46-47'. Can you explain this answer?
    Verified Answer
    Consider AB2 molecule Calculate % s-character in A—B bond:Corre...
    From Bent’s Rule equation,  cosx = s/s-1
    where x is an bond angle and s is the % s character in the bond, it is clear that if we increase bond angle, the %s Character will be maximum.
    Here angle is 150,
    ⇒ Cosx = s/(s-1)
    ⇒ Cos 150° = s/(s-1)
    ⇒ -0.86 = s/(s-1)
    ⇒ -0.86s +0.86 = s
    ⇒ 0.86 = 1.86s
    ⇒ s = 0.86/1.86
    ⇒ s = 0.462
    ⇒ %s = 0.462 X 10
    ⇒ %s = 46.2%
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    Most Upvoted Answer
    Consider AB2 molecule Calculate % s-character in A—B bond:Corre...
    Cos 150 = S/(S-1) ... - .886(S - 1) = S...and solving this we get S = 47 % ...
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    Community Answer
    Consider AB2 molecule Calculate % s-character in A—B bond:Corre...
    From the relation between bond angle and %s character it is known that with decreasing order of bond angle %s character decreases .
    Here the bond angle is 150 degree .
    For exactly sp hybridization 180 degree bond angle is required.But here (most probably) due to the repulsion between lone pair of A and A-B bonds ,i.e. lone pair-- bond pair repulsion , the bond becomes more bent resulting the bond angle of 150 degree.
    For exactly sp hybridization %s character is 50.
    As here the bond angle decreases so %s character will also decrease accordingly , resulting the %s character of 46-47 regarding the statement.
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    Consider AB2 molecule Calculate % s-character in A—B bond:Correct answer is '46-47'. Can you explain this answer?
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