Two Vertices of an equilateral triangle are (0,0) and (3, Root3). Find...
Sol:
Two vertices of an equilateral triangle are (0, 0) and (3, √3).
Let the third vertex of the equilaterla triangle be (x, y)
Distance between (0, 0) and (x, y) = Distance between (0, 0) and (3, √3) = Distance between (x, y) and (3, √3)
√(x2 + y2) = √(32 + 3) = √[(x - 3)2 + (y - √3)2]
x2 + y2 = 12
x2 + 9 - 6x + y2 + 3 - 2√3y = 12
24 - 6x - 2√3y = 12
- 6x - 2√3y = - 12
3x + √3y = 6
x = (6 - √3y) / 3
⇒ [(6 - √3y)/3]2 + y2 = 12
⇒ (36 + 3y2 - 12√3y) / 9 + y2 = 12
⇒ 36 + 3y2 - 12√3y + 9y2 = 108
⇒ - 12√3y + 12y2 - 72 = 0
⇒ -√3y + y2 - 6 = 0
⇒ (y - 2√3)(y + √3) = 0
⇒ y = 2√3 or - √3
If y = 2√3, x = (6 - 6) / 3 = 0
If y = -√3, x = (6 + 3) / 3 = 3
So, the third vertex of the equilateral triangle = (0, 2√3) or (3, -√3).
Two Vertices of an equilateral triangle are (0,0) and (3, Root3). Find...
Given Information:
Two vertices of an equilateral triangle are (0,0) and (3, √3).
Solution:
Step 1: Determine the distance between the two given vertices:
The distance between two points (x1, y1) and (x2, y2) is given by the distance formula:
d = √((x2-x1)^2 + (y2-y1)^2)
Using this formula, we can find the distance between (0,0) and (3, √3):
d = √((3-0)^2 + (√3-0)^2)
= √(9 + 3)
= √12
= 2√3
Step 2: Determine the midpoint of the line joining the given vertices:
The midpoint of a line segment with endpoints (x1, y1) and (x2, y2) is given by the formula:
Midpoint = ((x1+x2)/2, (y1+y2)/2)
Using this formula, we can find the midpoint of the line joining (0,0) and (3, √3):
Midpoint = ((0+3)/2, (0+√3)/2)
= (3/2, √3/2)
Step 3: Determine the third vertex of the equilateral triangle:
To find the third vertex, we need to rotate the midpoint 60 degrees counterclockwise around one of the given vertices.
Step 3.1: Determine the angle of rotation:
Since the triangle is equilateral, all angles are 60 degrees. We need to rotate the midpoint 60 degrees counterclockwise.
Step 3.2: Apply the rotation formula:
To rotate a point (x, y) counterclockwise by an angle θ, the new coordinates (x', y') can be found using the following formulas:
x' = x*cos(θ) - y*sin(θ)
y' = x*sin(θ) + y*cos(θ)
In our case, the angle of rotation is 60 degrees and the midpoint is (3/2, √3/2). So, the third vertex coordinates will be:
x' = (3/2)*cos(60) - (√3/2)*sin(60)
= (3/2)*(1/2) - (√3/2)*(√3/2)
= 3/4 - 3/4
= 0
y' = (3/2)*sin(60) + (√3/2)*cos(60)
= (3/2)*(√3/2) + (√3/2)*(1/2)
= (3√3)/4 + (√3)/4
= (4√3)/4
= √3
Therefore, the coordinates of the third vertex are (0, √3).
Conclusion:
The coordinates of the third vertex of the equilateral triangle, given that two vertices are (0,0) and (3, √3), are (0, √3).