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H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume of 1M NaOH solution should be added to 12g of NaH2PO4 to convert it into Na3PO4:
- a)100ml
- b)200 ml
- c)80ml
- d)300ml
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume ...
NaH^2PO^4 +2 NaOH →→Na^3PO^4 + H^2O
Thus according to this reaction 1 mol of NaH2PO4 react with 2 mol of NaOH.
Molar mass of NaH2PO4 = 120g/mol
Number of moles of NaH^2PO^4 in 12g = 12/120= 0.1 mol
Thus number of moles of NaOH required for complete reaction to occur = 2XX0.1 mol = 0.2 mol
Thus 0.2 mol NaOH is required for complete reaction.
Since molarity of NaOH is given to be 1 mol/L
This means volume of 1 mol NaOH = 1L
Thus volume of 0.2 mol NaOH = 1xx0.2 L = 0.2 L
= 0.2xx1000 mL = 200 mL
Therefore 200 mL of 1 M NaOH should be added to 12 g NaH2PO4 to exactly convert it into Na^3PO^4.
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H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume ...
Solution:
The reaction between NaH2PO4 and NaOH can be written as follows:
NaH2PO4 + 2NaOH → Na3PO4 + 2H2O
From the balanced chemical equation, it is clear that two moles of NaOH are required to convert one mole of NaH2PO4 into Na3PO4.
Given, the mass of NaH2PO4 = 12g
Molar mass of NaH2PO4 = 119.98 g/mol
Number of moles of NaH2PO4 = mass / molar mass = 12 / 119.98 = 0.1 mol
To convert 0.1 mol of NaH2PO4 into Na3PO4, we need 0.2 mol of NaOH (i.e., two moles of NaOH per mole of NaH2PO4)
Volume of 1M NaOH solution required = (0.2 mol) / (1 mol/L) = 0.2 L = 200 mL
Therefore, the correct answer is option B, which is 200 mL.
The reaction between NaH2PO4 and NaOH can be written as follows:
NaH2PO4 + 2NaOH → Na3PO4 + 2H2O
From the balanced chemical equation, it is clear that two moles of NaOH are required to convert one mole of NaH2PO4 into Na3PO4.
Given, the mass of NaH2PO4 = 12g
Molar mass of NaH2PO4 = 119.98 g/mol
Number of moles of NaH2PO4 = mass / molar mass = 12 / 119.98 = 0.1 mol
To convert 0.1 mol of NaH2PO4 into Na3PO4, we need 0.2 mol of NaOH (i.e., two moles of NaOH per mole of NaH2PO4)
Volume of 1M NaOH solution required = (0.2 mol) / (1 mol/L) = 0.2 L = 200 mL
Therefore, the correct answer is option B, which is 200 mL.
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H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume of 1M NaOH solution should be added to 12g of NaH2PO4 to convert it into Na3PO4:a)100mlb)200 mlc)80mld)300mlCorrect answer is option 'B'. Can you explain this answer?
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H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume of 1M NaOH solution should be added to 12g of NaH2PO4 to convert it into Na3PO4:a)100mlb)200 mlc)80mld)300mlCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume of 1M NaOH solution should be added to 12g of NaH2PO4 to convert it into Na3PO4:a)100mlb)200 mlc)80mld)300mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume of 1M NaOH solution should be added to 12g of NaH2PO4 to convert it into Na3PO4:a)100mlb)200 mlc)80mld)300mlCorrect answer is option 'B'. Can you explain this answer?.
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