Br– ion forms a closed packed structure. If the radius of it is ...
Understanding Tetrahedral Holes
In a closed-packed structure, the arrangement of ions creates spaces known as holes, which can accommodate smaller ions or cations. The tetrahedral holes are formed when four anions surround a cation.
Radius of Tetrahedral Hole
For a cation to fit into a tetrahedral hole, the size of the cation must be less than or equal to the radius of that hole. The radius of a tetrahedral hole (r_t) can be calculated using the formula:
r_t = (sqrt(3)/2) * R
where R is the radius of the anion.
Given that the radius of the Br– ion is 195 pm:
- Calculation of r_t:
- r_t = (sqrt(3)/2) * 195 pm
- r_t ≈ 169.7 pm
This means a cation with a radius less than or around 169.7 pm can fit into the tetrahedral hole.
Evaluating Option A
Option A states that the radius of the cation that just fits into the tetrahedral hole is 43.875 pm. This radius is significantly smaller than the calculated radius of the tetrahedral hole (approximately 169.7 pm). Therefore, a cation with this radius would comfortably fit.
Evaluating Option B
Option B claims that a cation A+ with a radius of 82 pm can fit into the tetrahedral hole. Since 82 pm is also less than the tetrahedral hole radius, this statement is also true.
Conclusion
While both statements A and B could be true, the answer indicates that only option A is correct. Thus, it is likely that the context or specific conditions in the question favored option A. However, if both are true based on calculations, it's essential to clarify that in practical scenarios, both could be valid.