Is the last digit of integer x2 – y2 a zero?1) x – y is an...
Given: x^2−y^2=(x−y)(x+y) = integer x^2−y^2=(x−y)(x+y)=integer. Question is the units digit of this integer zero, which can be translated as is x^2−y^2 x^2−y^2 divisible by 10.
(1) x−y=30mx−y=30m (where mm is an integer) --> if xx and yy are integers, then x+y=integer x+y=integer and x^2−y^2=30m∗(x+y)=30m∗integer x^2−y^2=30m∗(x+y)=30m∗integer, which is divisible by 10 BUT if x=30.75x=30.75 and y=0.75y=0.75, then x^2−y^2=(x−y)(x+y)=30∗31.5=945=integer x^2−y^2=(x−y)(x+y)=30∗31.5=945=integer, which is not divisible by 10. Not sufficient.
(2) x+y=70nx+y=70n (where nn is an integer) --> if xx and yy are integers, then x−y=integer x−y=integer and x^2−y^2=(x−y) ∗ 70n=integer∗70n x^2−y^2=(x−y)∗70n=integer∗70n, which is divisible by 10 BUT if x=69.75x=69.75 and y=0.25y=0.25, then x^2−y^2=(x−y)(x+y)=69,5∗70=4865=integer x^2−y^2=(x−y)(x+y)=69,5∗70=4865=integer, which is not divisible by 10. Not sufficient.
(1)+(2) x^2−y^2=30m ∗ 70n=integer x^2−y^2 = 30m∗70n = integer, Which is divisible by 10. Sufficient.
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Is the last digit of integer x2 – y2 a zero?1) x – y is an...
It depends on the last digit of integer x.
If the last digit of x is 0, 1, 5, or 6, then the last digit of x^2 will also be 0, 1, 5, or 6, respectively.
If the last digit of x is 2, 3, 7, or 8, then the last digit of x^2 will be 4, 9, 9, or 4, respectively.
If the last digit of x is 4 or 9, then the last digit of x^2 will be 6 or 1, respectively.
Therefore, it is not possible to determine the last digit of x^2 without knowing the last digit of x.
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