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A body starts from rest. What is the ratio of the distance travelled by the body during the 4th and 3rd second
- a)7/5
- b)5/7
- c)7/3
- d)3/7
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A body starts from rest. What is the ratio of the distance travelled b...
Given: Initial velocity (u) = 0
Time interval = 1 second
To find: Ratio of distance travelled in 4th and 3rd seconds
Formula used:
Distance travelled (s) = ut + 1/2 at^2
Where,
u = Initial velocity (0)
a = Acceleration (constant)
t = time
Calculation:
Let us assume the acceleration of the body as 'a'.
In the 3rd second:
Time (t) = 3 seconds
Distance travelled (s) = 0 + 1/2 a(3)^2 = 4.5a
In the 4th second:
Time (t) = 4 seconds
Distance travelled (s) = 0 + 1/2 a(4)^2 = 8a
Therefore,
Ratio of distance travelled in 4th and 3rd seconds = Distance travelled in 4th second / Distance travelled in 3rd second
= 8a / 4.5a
= 1.78
= 7/5 (Approximately)
Therefore, the ratio of the distance travelled by the body during the 4th and 3rd seconds is 7/5 (Option A).
Time interval = 1 second
To find: Ratio of distance travelled in 4th and 3rd seconds
Formula used:
Distance travelled (s) = ut + 1/2 at^2
Where,
u = Initial velocity (0)
a = Acceleration (constant)
t = time
Calculation:
Let us assume the acceleration of the body as 'a'.
In the 3rd second:
Time (t) = 3 seconds
Distance travelled (s) = 0 + 1/2 a(3)^2 = 4.5a
In the 4th second:
Time (t) = 4 seconds
Distance travelled (s) = 0 + 1/2 a(4)^2 = 8a
Therefore,
Ratio of distance travelled in 4th and 3rd seconds = Distance travelled in 4th second / Distance travelled in 3rd second
= 8a / 4.5a
= 1.78
= 7/5 (Approximately)
Therefore, the ratio of the distance travelled by the body during the 4th and 3rd seconds is 7/5 (Option A).
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A body starts from rest. What is the ratio of the distance travelled by the body during the 4th and 3rd seconda) 7/5 b) 5/7 c) 7/3 d) 3/7 Correct answer is option 'A'. Can you explain this answer?
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