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A man got 4 horse and 9 cows at Rs 1340. He sells the horse at a profit of 10% and cows at 20% and his whole gain is Rs 188. What price did he by the horse. Chapter pair of linear equation in two variable?
Most Upvoted Answer
A man got 4 horse and 9 cows at Rs 1340. He sells the horse at a profi...
H = horses
c = cows
4h + 9c = 1340 -------- (i)
4(10/100 h) + 9(20/100 c) = 188

0.4h + 1.8c = 188 -------- (ii)
Solving (i) and (ii) simultaneously

4h + 9c = 1340 -------- (i)

9c = 1340 – 4h
c = (1340 – 4h)/9
Substitute in (ii)

0.4h + 1.8(1340 – 4h)/9  = 188 -------- (ii)

3.6h + 1.8(1340 – 4h) = 1692
3.6 h - 7.2h  + 2412 = 1692
-3.6h = -720
h = 200
He paid Rs. 200 for each horse.
Total cost( 4×200) = 800.

That's all🙂
Community Answer
A man got 4 horse and 9 cows at Rs 1340. He sells the horse at a profi...
Introduction:
This problem involves the concept of pair of linear equations in two variables. We need to use algebraic equations to solve this problem.

Given Information:
- A man bought 4 horses and 9 cows for Rs 1340.
- He sells the horses at 10% profit and cows at 20% profit.
- His total gain is Rs 188.

Let:
- Cost of 1 horse = x
- Cost of 1 cow = y

Equations:
- 4x + 9y = 1340 (Equation 1)
- 1.1(4x) + 1.2(9y) - 1340 = 188 (Equation 2)

Solution:
- Simplifying Equation 2, we get: 4.4x + 10.8y = 1528 (Equation 3)
- Multiplying Equation 1 by 4.4, we get: 17.6x + 39.6y = 5896 (Equation 4)
- Subtracting Equation 3 from Equation 4, we get: 13.2x + 29.88y = 4368
- Solving for x, we get: x = 240
- Substituting x = 240 in Equation 1, we get: y = 100

Answer:
The man bought each horse for Rs 240.
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A man got 4 horse and 9 cows at Rs 1340. He sells the horse at a profit of 10% and cows at 20% and his whole gain is Rs 188. What price did he by the horse. Chapter pair of linear equation in two variable?
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