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The number of unpaired electron (s) present in the species [Fe(H2O)5(NO)]2+ which is formed during brown ring test is:
Correct answer is '3'. Can you explain this answer?
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The number of unpaired electron (s) present in the species [Fe(H2O)5(N...
Explanation:
The species [Fe(H2O)5(NO)]2 is formed during a brown ring test, which is used to detect the presence of nitrates in a solution.
Structure of [Fe(H2O)5(NO)]2:
The central iron atom is surrounded by five water molecules and one nitric oxide molecule. The nitric oxide molecule is a neutral ligand and is coordinated to the iron atom through the nitrogen end.
Electronic configuration of iron:
The electronic configuration of iron is [Ar] 3d6 4s2. The five water molecules are coordinated to the iron atom through the lone pairs of electrons present on the oxygen atom of each water molecule.
Unpaired electrons:
The unpaired electrons present in the [Fe(H2O)5(NO)]2 species can be determined using the following formula:
Number of unpaired electrons = (spin multiplicity - 1)/2
Spin multiplicity is determined by adding one to the number of unpaired electrons present in the d-orbitals of the iron atom.
In the case of [Fe(H2O)5(NO)]2, there are four unpaired electrons present in the d-orbitals of the iron atom. Therefore, the spin multiplicity is 2.
Number of unpaired electrons = (spin multiplicity - 1)/2
= (2-1)/2
= 1/2
However, the nitric oxide molecule also contributes one unpaired electron to the overall system. Therefore, the total number of unpaired electrons in [Fe(H2O)5(NO)]2 is 3.
Conclusion:
The correct answer is '3'.
The species [Fe(H2O)5(NO)]2 is formed during a brown ring test, which is used to detect the presence of nitrates in a solution.
Structure of [Fe(H2O)5(NO)]2:
The central iron atom is surrounded by five water molecules and one nitric oxide molecule. The nitric oxide molecule is a neutral ligand and is coordinated to the iron atom through the nitrogen end.
Electronic configuration of iron:
The electronic configuration of iron is [Ar] 3d6 4s2. The five water molecules are coordinated to the iron atom through the lone pairs of electrons present on the oxygen atom of each water molecule.
Unpaired electrons:
The unpaired electrons present in the [Fe(H2O)5(NO)]2 species can be determined using the following formula:
Number of unpaired electrons = (spin multiplicity - 1)/2
Spin multiplicity is determined by adding one to the number of unpaired electrons present in the d-orbitals of the iron atom.
In the case of [Fe(H2O)5(NO)]2, there are four unpaired electrons present in the d-orbitals of the iron atom. Therefore, the spin multiplicity is 2.
Number of unpaired electrons = (spin multiplicity - 1)/2
= (2-1)/2
= 1/2
However, the nitric oxide molecule also contributes one unpaired electron to the overall system. Therefore, the total number of unpaired electrons in [Fe(H2O)5(NO)]2 is 3.
Conclusion:
The correct answer is '3'.
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