Balance the equation C2H6 O2. -> H2O CO2 heat and light?
Balancing the Equation: C2H6 + O2 -> H2O + CO2 + heat and light
Introduction
The given equation represents the combustion of ethane (C2H6) in the presence of oxygen (O2) to produce water (H2O), carbon dioxide (CO2), heat, and light. Balancing the equation ensures that the number of atoms on both sides of the equation is equal, indicating the conservation of mass.
Balancing the Equation
To balance the equation, we need to ensure that the number of atoms of each element is equal on both sides. Let's break it down step by step:
Carbon (C)
The left side of the equation has 2 carbon atoms from the ethane molecule (C2H6). To balance it, we need 1 carbon atom on the right side. Therefore, we add a coefficient of 2 in front of CO2:
C2H6 + O2 -> 2CO2 + H2O + heat and light
Hydrogen (H)
On the left side, there are 6 hydrogen atoms from the ethane molecule (C2H6). To balance it, we need 3 hydrogen atoms on the right side. Therefore, we add a coefficient of 3 in front of H2O:
C2H6 + O2 -> 2CO2 + 3H2O + heat and light
Oxygen (O)
On the left side, there are 2 oxygen atoms from the ethane molecule (C2H6), and 2 oxygen atoms from the oxygen molecule (O2). To balance it, we need 4 oxygen atoms on the right side. Therefore, we add a coefficient of 2 in front of O2:
C2H6 + 2O2 -> 2CO2 + 3H2O + heat and light
Explanation
The balanced equation now represents the combustion of ethane (C2H6) with oxygen (O2) to form carbon dioxide (CO2), water (H2O), heat, and light. This reaction is highly exothermic, meaning it releases energy in the form of heat and light.
During the combustion process, ethane (C2H6) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). The heat and light energy are released due to the breaking and formation of chemical bonds. The reaction is considered a combustion reaction as it involves the rapid oxidation of a hydrocarbon fuel (ethane) in the presence of oxygen.
The balanced equation shows that for every 1 molecule of ethane, 2 molecules of carbon dioxide and 3 molecules of water are formed. The coefficients indicate the ratio of reactants and products in the reaction.
In summary, balancing the equation ensures the conservation of mass and provides a clear representation of the reactants and products involved in the combustion of ethane.