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In triangle ABC if AB/1=AC/2=BC/root3 then angleC=?
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? In triangle ABC if AB/1=AC/2=BC/root3 then angleC=?
AB = (1/2) AC  ,  BC = (sqrt3 /2) AC  --->  AB^2 + BC^2 = AC^2
then, <B = 90degree
sinC = AB/AC = 1/2  --->  <C = 30degree
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? In triangle ABC if AB/1=AC/2=BC/root3 then angleC=?
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