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When an object is placed at a distance of 40 cm from a concave spherical mirror the magnification produced is 1/2 where should the object be placed to get a magnification of 1/ 3 ?
Most Upvoted Answer
When an object is placed at a distance of 40 cm from a concave spheric...
U= -30
m = 1/2

we know that m = -v/u
so v = 15

1/f = 1/v + 1/u 
 
f = 10

for m= 1/3 

-v/u = 1/3
v= -(1/3 * u)

1/f = 1/v + 1/u

1/10 = 3/-u + 1/u 

1/10 = -4 /u 

u = -40 

therefore for the magnification to be 1/3 the object must be placed 40 cm in front of the mirror

That's all
Community Answer
When an object is placed at a distance of 40 cm from a concave spheric...
**Introduction**

To determine the position where an object should be placed to achieve a specific magnification with a concave spherical mirror, we will use the mirror formula and the magnification formula. The mirror formula is given as:

1/f = 1/v - 1/u

Where:
- f is the focal length of the mirror,
- v is the image distance from the mirror, and
- u is the object distance from the mirror.

The magnification formula is given as:

magnification (m) = -v/u

In this case, we are given that the magnification produced is 1/2 when the object is placed at a distance of 40 cm from the concave spherical mirror. We need to find the new position where the object should be placed to achieve a magnification of 1/3.

**Given Information**

- Object distance (u) = 40 cm
- Magnification (m) = 1/2

**Calculating the Focal Length**

First, we need to calculate the focal length (f) of the concave spherical mirror. We can rearrange the magnification formula to solve for v:

magnification (m) = -v/u -> v = -m * u

Substituting the given values:

v = - (1/2) * 40 cm = -20 cm

Now, we can substitute the values of v and u into the mirror formula and solve for f:

1/f = 1/v - 1/u

1/f = 1/(-20 cm) - 1/(40 cm)

1/f = -1/(20 cm)

f = -20 cm

The negative sign indicates that the mirror is concave.

**Calculating the New Object Distance**

Now, we need to find the new position where the object should be placed to achieve a magnification of 1/3. Let's assume the new object distance is x cm.

Using the magnification formula:

magnification (m) = -v/u

1/3 = -(-20 cm)/(x cm)

1/3 = 20 cm/x cm

Cross-multiplying:

x cm = 20 cm * 3

x cm = 60 cm

Therefore, the object should be placed at a distance of 60 cm from the concave spherical mirror to achieve a magnification of 1/3.

**Conclusion**

By using the mirror formula and the magnification formula, we determined that when an object is placed at a distance of 40 cm from a concave spherical mirror and the magnification produced is 1/2, the object should be placed at a distance of 60 cm to achieve a magnification of 1/3.
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When an object is placed at a distance of 40 cm from a concave spherical mirror the magnification produced is 1/2 where should the object be placed to get a magnification of 1/ 3 ?
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When an object is placed at a distance of 40 cm from a concave spherical mirror the magnification produced is 1/2 where should the object be placed to get a magnification of 1/ 3 ? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about When an object is placed at a distance of 40 cm from a concave spherical mirror the magnification produced is 1/2 where should the object be placed to get a magnification of 1/ 3 ? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When an object is placed at a distance of 40 cm from a concave spherical mirror the magnification produced is 1/2 where should the object be placed to get a magnification of 1/ 3 ?.
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